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Mikrokontrollerid ja robootika homework 1 - sarnased materjalid

Leidsid 33 sarnast õppematerjali, mis on seotud failiga "Mikrokontrollerid ja robootika homework 1". Need materjalid aitavad sul teemat sügavamalt mõista.

1111, bits, 1011, result, memory, address, binary, 0101, clock, following, part, 0111, equivalent, eeprom, cycle, convert, shift, string, numbers, 1001, variable, store, strings, chip, integral, base, logic, suitable, left, loop, assume, processor, pins, select, module, frequency, delay, command, sent, reading, directionend, signed, choose, without
Mictrocontroller Week 03
14
pdf

Mictrocontroller Week 03

Mictrocontroller Week 03 Numbering systems 1. Convert the decimal number 123.456 to the following formats, taking whole numbers and fractions into account. Show calculations. a) binary b) hexadecimal c) base-5 d) BCD === 1. a) 0111 1011.0111 01002 b) 7B.7416 c) 443.2125 d) 0001 0010 0011.0100 0101 01102 === 2. Extend the following unsigned 8-bit binary numbers to their 16-bit equivalents and convert the result to hexadecimal. a) 011010112 b) 101101012 === 2. a) 006B b) 00B5 === 3. Extend the following signed two’s complement 8-bit binary numbers to their 16-bit equivalents and convert the result to hexadecimal. a) 011010112 b) 101101012 === 3. a) 006B b) FFB5 === Logic and arithmetic 4. Using two’s complement arithmetic, calculate the following (choose a suitable number of bits for the representation): a) 121 – 185 b) -70 – 88 == 4. Convert back to verify answer == 5

Mehhatroonika
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Homework 01
2
docx

Homework 01

0,456*16= 7,296 ; 0,296*16=4,736; 0,736*16=11,776; 0,776*16=12,416; 0,416*16=6,656; 0,656*16=10,496; 0,496*16=7,936; 0,936*16=14,976; 0,976*16=15,616; 0,616*16=9,856; 0,856*16=13,696; 0,696*16=11,136; 0,136*16=2,176; 2,176*16=2,816; 0,816*16=13,056 Hex is 7B.74BC6A7EF9DB22D c) 123,456/5=24,6912/5=4,93824/5=0,987648 0,987648*5=4,93824; 0,93824*5=4,6912; 0,6912*5=3,456; 0,456*5=2,28; 0,28*5=1,4; 0,4*5=2; 0*5=0 base-5 is d)BCD is 2. a) Unsigned 16-bit binary is 0000000001101011. Hexadecimal is 6B b) Unsigned 16-bit binary is 0000000010110101. Hexadecimal is B5 3. a) Signed two's complement 16-bit binary is 0000000001101011. Hexadecimal is 6B. b) Signed two's complement 16-bit binary is 1111111110110101. Hexadecimal is FFB5 4. a) 1111001 +1111111101000111 1111111111000000 b) 10111010 + 10101000 1111111101100010 16-bits is suitable. 1 5. += (9+D=16; A+4+1= F; 3+2=5)

Mikrokontrollerid ja...
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CPM1A Programmable Controllers Operation Manual 1784470
402
pdf

CPM1A Programmable Controllers Operation Manual 1784470

Cat. No. W317-E1-11 SYSMAC CPM1A Programmable Controllers OPERATION MANUAL CPM1A Programmable Controllers Operation Manual Revised October 2007 iv Notice: OMRON products are manufactured for use according to proper procedures by a qualified operator and only for the purposes described in this manual. The following conventions are used to indicate and classify precautions in this manual. Always heed the information provided with them. Failure to heed precautions can result in injury to people or dam- age to property. ! DANGER Indicates an imminently hazardous situation which, if not avoided, will result in death or serious injury. Additionally, there may be severe property damage.

Automatiseerimistehnika
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Book Analog Interfacing to Embedded Microprocessors
568
pdf

Book Analog Interfacing to Embedded Microprocessors

Design Checklist 45 v 3 Sensors 47 Temperature Sensors 47 Optical Sensors 59 CCDs 72 Magnetic Sensors 82 Motion/Acceleration Sensors 86 Strain Gauge 90 4 Time-Based Measurements 93 Measuring Period versus Frequency 95 Mixing 97 Voltage-to-Frequency Converters 99 Clock Resolution 102 5 Output Control Methods 103 Open-Loop Control 103 Negative Feedback and Control 103 Microprocessor-Based Systems 104 On-Off Control 105 Proportional Control 108 PID Control 110 Motor Control 123 Measuring and Analyzing Control Loops 130 6 Solenoids, Relays, and Other Analog Outputs 137 Solenoids 137 Heaters 143 Coolers 148 Fans 149

Mehhatroonika
11 allalaadimist
Tööstuslik andmeside kontrolltöö 2 abimaterjal - vastused
3
doc

Tööstuslik andmeside kontrolltöö 2 abimaterjal - vastused

byte-oriented protocols) or the start-of-frame flag (for bit-oriented protocols) appears in the actual data. Intermediate Transmission Block) ·Same as ETB, except that the receiving statio Differs from HDLC because of multiaccess MAC that provides · Maximum payload length (default: 1500) This was not likely to happen in ASCII text, but is very likely with binary data. This is known as a data will not acknowledge after the error checking. EOT (End of Transmission) framing/error detection: · Type of CRC (2B or 4B) transparency problem an can be rectified with byte stuffing (for byte-oriented protocols) and bit ·Indicates that a station has no data to transmit

Tööstuslik andmeside
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Programmeerimiskeel
555
doc

Programmeerimiskeel

Response 1. 11131 0% Student Value Correct Answer Feedback Response 2. 11264 100% 3. 12522 0% 4. 1023 100% 5. 10037 0% Score: 0/10 2. Kuidas nimetatakse mälupesa, mis hoiab infot mälupesa kohta, kus asub programmi jaoks oluline informatsioon? Student Value Correct Answer Feedback Response 1. Direct 0% address 2. Count 0% 3. Flag 0% 4. Pointer 100% 5. Loop 0% Score: 0/10 3. Kui palju mälu on Ecki xComputer´l? Student Value Correct Answer Feedback Response 1. 512 B 0% 2. 1KB 0% 3. 2KB 100% 4. 4KB 0% Score: 0/10 4. Kas register ja mälupesa on samad asjad? Student Value Correct Answer Feedback Response 1

Infotehnoloogia
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Homework 1 in Microcontrollers and practical robotics
3
docx

Homework 1 in Microcontrollers and practical robotics

0.456 * 2 = 0.912 0 0.912 * 2 = 1.824 1 0.824 * 2 = 1.642 1 0.642 * 2 = 1.284 1 0.284 * 2 = 0.568 0 0.568 * 2 = 1.136 1 0.136 * 2 = 0.272 0 0,544 * 2 = 0,544 0 b)1111011.01110100 to hex 0111 => 7 1011 => 11 0111 => 7 0100 => 4 and so on.. answer is: 7B.74 c) 123.456 to base-5 100 = 400 20 = 40 3=3 400 + 40 + 3 = 443 5^-1 = 0,2 5^-2 = 0,04 5^-3 = 0,008 0,456/0,2 = 2 0,056/0,04 = 1,4 0,4/0,2 = 2 Final answer 443.212 d) 1 = 0001 2 = 0010 3 = 0011 4 = 0100 5 = 0101 6 = 0110 0001 0010 0011.0100 0101 0110 2) a) 16bit equivalent is a) 0000000001101011 the answer is 006B 1011 is in dec 11 and in hex B 0110 is in dec 6 and in hex also 6 b) 16bit equivalent is b) 0000000010110101 the answer is 00B5 0101 is in dec 5 and in hex also 5 1011 is in dec 11 and in hex B 3) 16bit equivalents to hex a) 0000000001101011 => 006B b) 1111111110110101 => FFB5 4) a) 121 - 185 = -64 in binary it is 11000000 ( 1 in front of 1000000 shows a negative number)

Mikrokontrollerid ja...
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Homework 2 Week 4
12
docx

Homework 2 Week 4

Week 4 homework. Question 1: 1. SNR – Ratio of root mean square signal to root mean square. 2. SINAD – Ratio of the RMS signal amplitude to the mean of value of the root sum square. 3. ENOB – The effective number of bits and relates to SINAD. 4. THD – Ratio of the rms value of the fundamental signal to the mean value of RSS of its harmonics. 5. SFDR – Ratio of the RMS value of the signal to the RMS value of the worst spurious signal. 6. Channels – multiple analog signal inputs to the ADC that can be individually selected or selected through a multiplexor. 7. Linearity – Describes how an ADC conveter follows a linear function. 8

Inglise keel
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Elektroonika Alused
46
doc

Elektroonika Alused

-- Autor: Merike Hein --> Kahendarvu teisendused teistesse koodidesse Binaarkood Positiivsete arvude märgibitt on 0, negatiivsetel 1. Kümnendkood, kui Kümnendkood, kui H Binaarkood binaararv on H Binaarkood binaararv on otsekoodis täiendkoodis otsekoodis täiendkoodis F 1111 15 -1 7 0111 7 +7 E 1110 14 -2 6 0110 6 +6 D 1101 13 -3 5 0101 5 +5 C 1100 12 -4 4 0100 4 +4 B 1011 11 -5 3 0011 3 +3

Elektroonika alused
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Mikrokontrollerid ja robootika homework 2
14
pdf

Mikrokontrollerid ja robootika homework 2

83V? 15 bit = 32768 10V/ 32768 = 0,0003 V 6,83V / 0,0003 = 22767 22767 = 01011000 111011112 Question 4 What is the value of the quantization error between an input voltage of 2.3V and quantized voltage with the output code word equal to 011101012 using an 8 bit ADC with 5V reference? 011101012 = 117 Correspond to 5V * 117/256 = 2.2852V Error = 2,3V – 2.2852 = 0,0148V Question 5 A digital multimeter is designed to have a readout with four decimal digits. How many bits will be required in its ADC? MAX = 9999 213 = 8192 214 = 16384 (too many digits) 13 Bit will be required in ts ADC. Question 6 Draw a circuit diagram of a 2 bit flash ADC using only resistors, comparators and NAND gates. Question 7 Given the following dual-slope ADC: a) How long would it take for this ADC to complete the run-up phase? 𝑅𝐶 𝑡𝑢𝑝 = − ∙ 𝑉𝑜𝑢𝑡 = −400𝜇𝑠 𝑉𝑖𝑛

Mikrokontrollerid ja robootika
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Emaplaadi terminite sõnastik inglise keeles
5
docx

Emaplaadi terminite sõnastik inglise keeles

motherboard AGP - Accelerated Graphics Port - a high speed interface for video cards; runs at 1X (66MHz), 2X (133MHz), or 4X (266MHz). PCI - Peripheral Component Interconnect - a high speed interface for video cards, sound cards, network interface cards, and modems; runs at 33MHz. ISA - Industry Standard Architecture - a relatively low speed interface primarily used for sound cards and modems; runs at approx. 8MHz. RAM - Random Access Memory - see System RAM Port (serial, parallel, PS/2, USB, sound, LAN, VGA, SCSI) - interface connectors for the associated types of devices Serial - a low speed interface typically used for mice and external modems Parallel - a low speed interface typically used for printers PS/2 - a low speed interface used for mice and keyboards USB - Universal Serial Bus - a medium speed interface typically used for mice, keyboards,

Arvutitund
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Mikrokontrollerid ja robootika kodutöö 4
18
docx

Mikrokontrollerid ja robootika kodutöö 4

Read Chapter_4_Time_Based_Measurements.pdf Question 1 When converting an analogue value to a frequency, consider the following diagram describing the system. The frequency changes from 20 MHz to 18 MHz and the system samples at an interval of 2ms. How many counts does the microprocessor detect at, 2ms a) 20 MHz? =40000 counts 50 ns 2ms b) 18 MHz? =36 000 counts 55,55 ns What is the difference in terms of number of counts detected by the microprocessor? Between 20MHz and 18MHz are 4000 counts. Question 2

Mikrokontrollerid ja robootika
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Lühendite seletus
120
doc

Lühendite seletus

A... AA Auto Answer AAA Authentication, Authorization and Accounting AAB All-to-All Broadcast AAC Advanced Audio Coding AACS Advanced Access Control System AAL Asynchronous Transfer Mode Adaption Layer AAM Automatic Acoustic Management AAP Applications Access Point [DEC] AARP AppleTalk Address Resolution Protocol AAS All-to-All Scatter AASP ASCII Asynchronous Support Package AAT Average Access Time AATP Authorized Academic Training Program [Microsoft] .ABA Address Book Archive (file name extension) [Palm] ABAP Advanced Business Application Programming [SAP] ABC * Atanasoff-Berry Computer (First digital calculating machine that used vacuum tubes) ABEND Abnormal End ABI Application Binary Interface ABIOS Advanced BIOS

Informaatika
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Mikrokontrollerid ja praktiline robootika
14
pdf

Mikrokontrollerid ja praktiline robootika

Homework-04 Solution (100 marks) Read Chapter_4_Time_Based_Measurements.pdf Question 1 (10 marks) When converting an analogue value to a frequency, consider the following diagram describing the system. The frequency changes from 20 MHz to 18 MHz and the system samples at an interval of 2ms. How many counts does the microprocessor detect at, a) 20 MHz? b) 18 MHz? What is the difference in terms of number of counts detected by the microprocessor? Solution: 1 1 a) Converse 20 MHz to time length: T    0.00005ms f 20,000,000

Informaatika
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Kommunikatsioonimudel
102
pdf

Kommunikatsioonimudel

1. Üldine kommunikatsioonimudel Sõnumi allikas->saatja(allikast info)->edastussüsteem->vastuvõtja->sihtjaam [üheks näiteks võiks olla: Arvuti->modem->ÜKTV->modem->arvuti] sisendinfoAllikas(sisendandmed g(t))->edastaja e. transmitter(edasi saadetud signaal s(t))->edastussüsteem(saadud signaal r(t))->vastuvõtja(väljund andmed g'(t))- >lõppunkti saaväljund informatsioon m' 2. Kommunikatsioonisüsteemi ülesanne • mõistlik kasutamine/koormamine • liidestus(kokku ühendamine. Ntx: võrk+võrk, arvuti+võrk) • Signaalide genereerimine(edastamine)(signaalide ühest süsteemist teise üleviimine) • Sünkroniseerimine [andmeedastuse algust(saatja) ja lõppu(vastuvõtjat)] • Andmeside haldamine • Vigade avastamine ja parandamine(näiteks side mürarikkas keskkonnas) • Voojuhtimine (vastuvõtja saab pakette vastu võtta kindla kiirusega->on vaja kont

Tehnoloogia
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Projekt
11
pdf

Projekt

the sender to the addressee between one or several participants. SIP describes only rules of connection between devices, therefore together with SIP the information transfer protocol is used. SIP uses for data transmission protocols RTP (Real-Time Protocol) and SDP (Session Description Protocol). So, let's make a simple configuration between two PBXs. Figure 5.The scheme of SIP connection Stations' data: PBX 1 address: http://192.168.252.41 PBX 2 address: http://192.168.252.42 User: admin User: admin Pass: trikstriks Pass: trikstriks Phone Numbers: 100-199 Phone Numbers: 200-299 To configure a SIP connection between PBX 1and PBX 2, first of all we need to go to their addresses (http://192.168.252.41 http://192.168.252.42). We write given User name and Password. Firstly, let configure SIP Trunks

Andmeside
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Sissejuhatus infotehnoloogiasse konspekt
138
docx

Sissejuhatus infotehnoloogiasse konspekt

lahendada. 1. Lepime sellega, et mõnes olukorras ei õnnestu vastust leida 2. Valime vahel juhuslikult, ehk: teeme vahel vigu  The five types of information that are the only types the computer commonly manipulates:  Visual (pictures)  Numeric (numbers)  Character (text)  Audio (sound)  Instructions (programs) Modern computers work in a system of numbers called binary numbers  Binary numbers:  Similar to familiar decimal system.  Uses only two symbols: 0 and 1.  The choice of using binary numbers is dictated by cost and reliability.  Binary circuits:  Electronic circuits are cheapest and most reliable if they only assume two states or conditions.  These binary circuits have only two states, ON or OFF.

Sissejuhatus...
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Games Programming with Java and Java 3D
23
pdf

Games Programming with Java and Java 3D

Individual game sales are also increasing: Grand Theft Auto: Vice City from Take Two Interactive sold 1 Games Programming with Java and Java 3D an estimated 3 million copies in its first month of release. This game is likely to become the best selling title of 2002, and of all time. 1.2. Console Hardware Since consoles are so central to gaming, it is interesting to consider their capabilities. The PlayStation 2 processor runs with a clock speed of 294 MHz, has 32Mb of RAM, and a separate graphics chip that can render about 66 million polygons per second. The small amount of RAM is an important constraint upon games wishing to use Java. The introduction of the Xbox changed the game rules (so to speak), with its Pentium III, 64Mb RAM, a 8Gb hard disk, and the ability to render 150-200 million polygons per second. Sony and Microsoft have recently released network adapters for their consoles,

Java programmeerimine
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Introduction of SCM
40
doc

Introduction of SCM

These organizations have their own objectives and these are often conflicting. Marketing's objective of high customer service and maximum sales dollars conflict with manufacturing and distribution goals. Many manufacturing operations are designed to maximize throughput and lower costs with little consideration for the impact on inventory levels and distribution capabilities. Purchasing contracts are often negotiated with very little information beyond historical buying patterns. The result of these factors is that there is not a single, integrated plan for the organization---there were as many plans as businesses. Clearly, there is a need for a mechanism through which these different functions can be integrated together. Supply chain management is a strategy through which such integration can be achieved. 2 IMPLICATIONS OF SCM ON LOGISTIC MANAGEMENT

3 allalaadimist
Inglise keel unit 5 answers
276
docx

Inglise keel unit 5 answers

[10] 7. (i) plasmid cut by restriction enzyme; at specific sequence; same enzyme as used to cut (insulin) gene; sticky ends / described; ref. complementary sticky ends; ligase seals (sugar-phosphate) backbone / AW; max 4 (ii) credit any two from the following: 1 antibiotic resistance (gene) introduced and survivors have plasmid; 2 fluorescent marker (gene) introduced and glowing bacteria have plasmid; 3 identify bacteria producing insulin using antibodies; 2 [6] 8. referring to pig insulin: ethical / religious, reasons;

Inglise keel
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W05 Homework3 Solutions
20
pdf

W05 Homework3 Solutions

15°C +25°C = 298.15°C R60% 30°C =25.5858 kΩ - Matlab code: 33*exp(4600*(1/303.15-1/298.15)) = 25.5858 Calculate the Humidity Sensor resistance at relative humidity 70% See the above graphic for the standard resistance: Exercises - Solutions 3 R60% 25°C =33 kΩ, R70% 25°C =12 kΩ R70% 30°C=( R60% 30°C * R70% 25°C =)/ R60% 25°C =9.2 kΩ Or RH = 9.2 kΩ, give RT = 50 kΩ VO = RH/(RT+RH)*2.5V = 0.388 V Question 3 Given the following bridge circuit for a strain gauge, determine the value of the strain gauge resistance {RS}. Let: VIN = 5V R3 = 200 Ω R2 = 50 Ω R1 = 100 Ω a) Under no strain. b) When VOUT = 0.5 V {under strain}. Solution: a) Under no strain:  R1 R3   R1R4  R2 R3  VOUT     IN  V   VIN

Mehhatroonika
5 allalaadimist
Järjestuste võrdlemine-otsingud andmebaasidest-BLAST-FASTA-SW-
23
doc

Järjestuste võrdlemine, otsingud andmebaasidest (BLAST, FASTA, SW).

xii. Primaadid Vastus: gi|83674984|gb|ABC40672.1| rcTPI1 [Gorilla gorilla] 192 4e-48 f. Võrrelda erinevatele valkudele leitud liikide identsustasemeid (%). Milline grupp on selle põhjal kõige lähedasem ja milline kõige kaugem sugulane leitud järjestusele. VASTUS: Kõige lähedasem on: Bacteria triosephosphate isomerase [Escherichia coli O157:H7 EDL933] Score = 520 bits (1338), Expect = 1e-145 Identities = 255/255 (100%) Kõige kaugem on: Protozoa, keda üldse ei leitudki. Viirused hypothetical protein [Ostreococcus virus OsV5] Score = 32.7 bits (73), Expect = 5.8, Identities = 16/46 (34%) 2. BLAST programmi kasutamine valgumotiivide otsimisel. a. Valida sobiv programm sarnasuste leidmiseks motiivile VEHINKTIAPALVSK ning valida otsimiseks andmebaas, mis sisaldab kõik

Bioinformaatika
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SISSEJUHATUS ITSSE
21
docx

SISSEJUHATUS ITSSE

1. Suuruse numbrid ja mida nad tähendavad ? 1 bit = 1 binary digit 1bait = 8bitti 1kilobait = 1024 baiti Megabait = 1,048,576 baiti Gigabait = 1,073,741,824baiti Terabait = 1 trillion baiti Esimene mikroprose: intel 4004 von Neumann-type computer - Stored-program Computer KÜSIMUSED: Nimeta vähemalt üks oluline teooria- alane tulemus Alan Turingilt. Millisel aastakümnel see tulemus saadi? Turingu test 1940 Millal loodi programmeerimiskeel Fortran (pluss- miinus kolm aastat on OK)? Mille poolest on Fortran eriline

Sissejuhatus...
127 allalaadimist
Tarkvara kokkuvõte inglise keeles
36
doc

Tarkvara kokkuvõte inglise keeles

The Model •The model defines an abstract view to the problem. This implies that the model focuses only on problem related stuff and that you try to define properties of the problem. These properties include: 1 •the data which are affected and 2 •the operations which are identified by the problem. Object-oriented Paradigm •Everything is an object •A program is a bunch of objects telling each other what to do by sending messages •Each object has its own memory made up of other objects •Every object has a type •All objects of a particular type can receive the same messages Domain Model •A domain model does not represent the entire domain as it is in the real world. It includes only the concepts that are needed to support the application. Object •Is a partitioned area of memory where object code is stored •The area of memory is protected •This code can function relatively independently of other objects

Tehnoloogia
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Vormistamine ülesanne 2
20
docx

Vormistamine ülesanne 2

FIGURE 2. Martindale pilling tester. In Pilling Box (see Figure 3) samples are mounted on polyurethane tubes and are tumbled in cork- lined rotating wooden boxes. Accordingly, the samples move under the condition of no pressure and the specimens are conducted under mutual transient touching. As a consequence, unlike the Martindale method, the rubbing for the samples is random. Whichever is the device (Martindale or Pilling Box), the final result consists of abraded fabrics to be assessed in terms of pilling. This is performed by skilled operators (experts) comparing the specimens, after a predefined number of cycles performed by the testing equipment, with visual standards (which may be actual fabrics samples or photographs). On the basis this comparison, the experts define the resistance to pilling using the so called “degree of pilling” [1] i.e. an index

Andme-ja tekstitöötlus
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Study of heat transfer coefficient in helical coil
52
docx

Study of heat transfer coefficient in helical coil

CHEMICAL ENGINEERING DEPARTMENT PORTUGAL Marvin Üürike Tallinn University of Technology Faculty of Chemical and Materials Technology Department of Chemical Engineering Estonia ERASMUS PROJECT STUDY OF THE HEAT TRANSFER COEFFICIENT IN A HELICAL COIL Supervisor: Albina Ribeiro Porto 2015 2 Abstract The following work investigates overall heat transfer coefficient of a helical coil and how it changes in different situations. The variables investigated were flow rate inside a submerged helical coil and agitation of the bath. To investigate the change in heat transfer coefficient in different situations, a simple experiment was set up. It consisted of a rectangular isolated tank, which was filled with water, submerged steel coil and an agitator. A rotameter was used to measure the flow rate, and a

2 allalaadimist
Ford escorti käsiraamat
256
pdf

Ford escorti käsiraamat

1·4 Maintenance schedule Every 12 000 miles (20 000 km) or 12 months - whichever comes first Every 250 miles (400 km) or weekly In addition to all the items in the 6000 mile (10 000 km) service, carry out the following: See "Weekly checks" On OHV and HCS engines check and if necessary adjust the valve clearances (Section 21) Check the exhaust system condition and security (Section 22)

Auto õpetus
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The 4-Hour Body - An Uncommon Guide to Rapid Fat-Loss-Incredible Sex-and Becoming Superhuman - Timothy Ferriss
574
pdf

The 4-Hour Body - An Uncommon Guide to Rapid Fat-Loss, Incredible Sex, and Becoming Superhuman - Timothy Ferriss

before doing anything in this book. PUBLISHER'S DISCLAIMER The material in this book is for informational purposes only. As each individual situation is unique, you should use proper discretion, in consultation with a health care practitioner, before undertaking the diet, exercises, and techniques described in this book. The author and publisher expressly disclaim responsibility for any adverse effects that may result from the use or application of the information contained in this book. ON THE SHOULDERS OF GIANTS I am not the expert. I'm the guide and explorer. If you nd anything amazing in this book, it's thanks to the brilliant minds who helped as resources, critics, contributors, proofreaders, and references. If you nd anything ridiculous in this book, it's because I didn't heed their advice.

Inglise keel
20 allalaadimist
Letters
38
doc

Letters

the letter would look impolite. · There are certain characteristics which allow us to distinguish between formal and informal letters. These are: ~ The salutation (e.g. Dear Sir/Madam, Dear Bill) ~ The style or language (e.g. use of formal language for formal letters, or the use of slang and idioms for informal letters) ~ The closing remarks (e.g. Yours faithfully, Lucy Cohen ; Yours sincerely, Lucy Cohen / Love, Lucy) Note: 1. In formal letters your address and the date as well as the recipient's address are included in the letter. When you do not know the name of the recipient, you should include their title in the address. e.g. The Director of Studies, St Michael's School, 15, Pine St., London. You should begin the letter with Dear Sir/Madam, and end with Yours faithfully, Peter Jones. When the name of the recipient is known, their name and title should be included in their address, e.g. Mr Witkins, Accounts Manager, Rockdell

Inglise keel
32 allalaadimist
Connecting Ideas Logically and Effectively
7
doc

Connecting Ideas Logically and Effectively

You will also need to know how to present different shades of argument to produce logically a recommendation you wish to make. This requires an ability to emphasise certain facts and 'bury' others. However, all facts need to be linked to give a logical flow. This unit will give you language practice in this important aspect of producing written documents. Evaluation Exercise 1 Connectives Study the following two versions of the same text and decide which do you find easier to read and why? what is the difference between them? When the ICN equipment was first introduced, it was found to provide a flexible and advanced system. Its speed of operation was greater than comparable hardware then available. In recent months major faults have developed in the equipment. The local agent appears incapable of providing a reliable repair service. The system is regularly out of

Inglise keel
54 allalaadimist
Side konspekt 2020- eksami kordamisküsimused
45
docx

Side konspekt 2020 / eksami kordamisküsimused

per inch). Seotud sellesosas, et pikslid võivad olla eri suurustega. (suurem ekraan ei tähenda, et on rohkem piksleid, vaid seal võivad olla suuremad pikslid, mis viivad PPI indeksi alla(teravus häguneb)). 40. Mida tähendab kui helisignaal on salvestatud 24 bitisügavuse ja 48 kHz? Mida need parameetrid tähendavad? In digital audio using pulse-code modulation (PCM), bit depth is the number of bits of information in each sample, and it directly corresponds to the resolution of each sample. Examples of bit depth include Compact Disc Digital Audio, which uses 16 bits per sample, and DVD-Audio and Blu-ray Disc which can support up to 24 bits per sample. 48kHz viitab Sampling-ule (signal processing) - it is the reduction of a continuous- time signal to a discrete-time signal. A common example is the conversion of a

Side
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Inglise leksikoloogia kordamisküsimuste vastused
24
doc

Inglise leksikoloogia kordamisküsimuste vastused

The first word of the pair comes down from Old English whereas the second one is a Scandinavian borrowing. Examples of native doublets are 'shadow' ('тень') and 'shade! Both are derived from the same Old English word 'sceadu'. 'Shade' is developed from the Nominative case, 'sceadu' is derived from oblique ease 'sceadwe'. The words 'drag' and 'draw' both come from Old English 'dragan' ('тащить') Etymological doublets also arise as a result of shortening when both the shortened form and the full form of the word are used: 'defense' - 'защита' - 'fence' - ''забор'; 'history' - 'история' - 'story' - 'рассказ'. Examples of ETYMOLOGICAL TRIPLETS (i.e. groups of three words of common root) are few in number: hospital (Lat.) - hostel (Norm.Fr.) - hotel (Par.. Fr.); to capture (Lat.) - to catch (Norm. Fr.) - to chase (Par. Fr.). 15. Folk etymology = popular etymology Folk’ or ‘popular’ theories (i.e

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Structural Testing Of Homebuilt Aircraft
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Structural Testing Of Homebuilt Aircraft

wing. During that sudden pull-up, the consider an extensive, detailed and stresses. Experienced designers like wing generates a lift that is by a "load complex wing testing project, a great to over-dimension this area of the factor" larger than the weight of the deal can be accomplished with very main spar (and the local reinforced aircraft. The result is that the reaction simple means. A structural testing of rib). Others become experienced to this suddenly increased lifting force the wing as will be described here designers after building - and testing - presses the pilot onto his seat with requires so little money, time and hot two or three wings. The one-piece the amount equal to that "load factor" coffee that we will really have diffi- wing experiences the highest bending times his weight

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