Homework 01 (0)

Masinaehitus - Mikrokontrollerid ja praktiline robootika

5 VÄGA HEA

Homework

a)123/2= 61,5; 61/2=30,5; 30/2=15; 15/2=7,5; 7/2= 3,5; 3/2=1,5
(1111011)
0.456*2=0.912; 0,912*2=1,824; 0,824*2=1,648; 0,648*2=1,296; 0,296*2=0,592; 0,592*2=1,184; 0,184*2=0,368; 0,368*2=0,736; (0,736*2=1,472; 0,472*2=0,944; 0,944*2=1,888)
So
b)123/16= 7,6875 ; 0,6875*16=11 ; 7/16 is less than one, then hex is 7B
0,456*16= 7,296 ; 0,296*16=4,736; 0,736*16=11,776; 0,776*16=12,416; 0,416*16=6,656; 0,656*16=10,496; 0,496*16=7,936; 0,936*16=14,976; 0,976*16=15,616; 0,616*16=9,856; 0,856*16=13,696; 0,696*16=11,136; 0,136*16=2,176; 2,176*16=2,816; 0,816*16=13,056
Hex is 7B.74BC6A7EF9DB22D
c) 123,456/5=24,6912/5=4,93824/5=0,987648
0,987648*5=4,93824; 0,93824*5=4,6912; 0,6912*5=3,456; 0,456*5=2,28; 0,28*5=1,4; 0,4*5=2; 0*5=0
base -5 is
d)BCD is

a) Unsigned 16-bit binary is 0000000001101011. Hexadecimal is 6B
b) Unsigned 16-bit binary is 0000000010110101. Hexadecimal is B5

a) Signed two’s complement 16-bit binary is 0000000001101011.
Hexadecimal is 6B.
b) Signed two’s complement 16-bit binary is 1111111110110101. Hexadecimal is FFB5

a) 1111001
+1111111101000111
1111111111000000
b) 10111010
+ 10101000
1111111101100010 16- bits is suitable .
1

+=
(9+D=16; A+4+1= F; 3+2=5)

Y=X shl 3

(A and B) or ((not A) and (not B))

Y = true
for i from 1 to 20
for j from 1 to 8, excluding 3
bitindex = j + (i-1)*8
if S1[bitindex] ≠ S2[bitindex]
Y = false
Exit loop
end
end
end

A) V and C (the operation produced an overﬂow and the operation produced a carry )
b) N (The result of the operation is negative )

4
3
2
1
10
17
memory chip

a) Suitable clock frequency 0 – 400 kHz
b) The loop lasts 1 µs (1/16*4*4). The delay should be for half (5 µs) the clock period.

Connect the following pins:
MAX232:T1IN ↔ PIC:Tx
MAX232:R1OUT ↔ PIC:Rx
MAX232:R1IN ↔ RS232 :TxD
MAX232:T1OUT ↔ RS232:RxD

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a)123/2= 61,5; 61/2=30,5; 30/2=15; 15/2=7,5; 7/2= 3,5; 3/2=1,5 (1111011)0.456*2=0.912; 0,912*2=1,824; 0,824*2=1,648; 0,648*2=1,296; 0,296*2=0,592; 0,592*2=1,184; 0,184*2=0,368; 0,368*2=0,736; (0,736*2=1,472; 0,472*2=0,944; 0,944*2=1,888)So 123,456_10=〖01111011.01110100〗_2)123/16= 7,6875 ; 0,6875*16=11 ; 7/16 is less than one, then hex is 7B0,456*16= 7,296 ; 0,296*16=4,736; 0,736*16=11,776; 0,776*16=12,416; 0,416*16=6,656; 0,656*16=10,496; 0,496*16=7,936; 0,936*16=14,976; 0,976*16=15,616; 0,616*16=9,856; 0,856*16=13,696; 0,696*16=11,136; 0,136*16=2,176; 2,176*16=2,816; 0,816*16=13,056Hex is 7B.74BC6A7EF9DB22Dc) 123,456/5=24,6912/5=4,93824/5=0,987648 0,987648*5=4,93824; 0,93824*5=4,6912; 0,6912*5=3,456; 0,456*5=2,28; 0,28*5=1,4; 0,4*5=2; 0*5=0base-5 is 〖443,212〗_5d)BCD is 〖0001 0010 0011.0100 0101 0110〗_2a) Unsigned 16-bit binary is 0000000001101011. Hexadecimal is 6Bb) Unsigned 16-bit binary is 0000000010110101. Hexadecimal is B5

Homework binary

Sarnased õppematerjalid

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Mikrokontrollerid ja robootika homework 1

Mictrocontroller Week 03 Numbering systems 1. Convert the decimal number 123.456 to the following formats, taking whole numbers and fractions into account. Show calculations. a) Binary Fractional part : Reading direction Integral part: Reading direction 0,456 x 2 = 0,912 0 123 / 2 = 61 1 0,912 x 2 = 1,812 1 61 / 2 = 30 1 0,812 x2 = 1,624 1 30 / 2 = 15 0 0,624 x 2 = 1,248 1 15 / 2 = 7 1 0,248 x 2 = 0,496 0 7/2=3 1 0,496 x 2 = 0,992 1 3/2=1 1 0 1 1 0 0 So 123.45610 = 0111 1011.0111 01002 b) Hexadecimal Fractional part :

Mikrokontrollerid ja robootika

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Homework 1 in Microcontrollers and practical robotics

Homework 1 in Microcontrollers and practical robotics 1) a) 0 123.456 - 64 = 59.456 1 59.456 - 32 = 27.456 1 27.456 - 16 = 11.456 1 11.456 - 8 = 3.456 1 3.456 - 4 = 0 3.456 - 2 = 1.456 1 1 0.456 * 2 = 0.912 0 0.912 * 2 = 1.824 1 0.824 * 2 = 1.642 1 0.642 * 2 = 1.284 1 0.284 * 2 = 0.568 0 0.568 * 2 = 1.136 1 0.136 * 2 = 0.272 0 0,544 * 2 = 0,544 0 b)1111011.01110100 to hex 0111 => 7 1011 => 11 0111 => 7 0100 => 4 and so on.. answer is: 7B.74 c) 123.456 to base-5 100 = 400 20 = 40 3=3 400 + 40 + 3 = 443 5^-1 = 0,2 5^-2 = 0,04 5^-3 = 0,008 0,456/0,2 = 2 0,056/0,04 = 1,4 0,4/0,2 = 2 Final answer 443.212 d) 1 = 0001 2 = 0010 3 = 0011 4 = 0100 5 = 0101 6 = 0110 0001 0010 0011.0100 0101 0110 2) a) 16bit equivalent is a) 0000000001101011 the answer is 006B 1011 is in dec 11 and in hex B 0110 is in dec 6 and in hex also 6 b) 16bit equivalent is b) 0000000

Mikrokontrollerid ja praktiline robootika

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