docstxt/133656757994735.txt
L=1H R=7.9 f=79 Hz Ur=10V Fig. 1.1 Circuit diagram Calculations: =2f=2**79=496,4 rad/s XL=L=1*496,4 Z=SQRT(XL2+R2)=SQRT(496,42+7,92)=496,5 I=UR/R=10/7,9=1,3A U=I*Z=1,3*496,5=645,5V UMAX=SQRT(2)*U=912,9V =-arccos(R/Z)=-89° =-89°/(360*79)=-3,1*10-3 A=-20*log(Z/R)=-36 dB Comparative data table: Quantity Calculated value Experimental value I, A 1,3 1,308 ° -89 -89,118
docstxt/127065387414363.txt
$ 3 5.0E-6 10.20027730826997 50 5.0 50 L 696 136 600 136 0 0 false 5.0 0.0 L 696 168 600 168 0 0 false 5.0 0.0 L 696 200 600 200 0 0 false 5.0 0.0 L 696 232 600 232 0 0 false 5.0 0.0 L 696 360 584 360 0 0 false 5.0 0.0 L 696 392 584 392 0 0 false 5.0 0.0 L 696 424 584 424 0 0 false 5.0 0.0 L 696 456 584 456 0 0 false 5.0 0.0 x 554 143 580 149 0 24 a0 x 545 368 572 374 0 24 b0 154 816 120 880 120 1 2 0.0 150 816 152 872 152 1 2 0.0 w 696 112 696 136 0 w 736 360 696 360 0 w 736 128 816 128 0 w 696 112 760 112 0 w 760 112 816 112 0 w 816 144 760 144 0 w 760 144 760 112 0 w 736 360 736 168 0 w 736 168 736 160 0 w 736 160 816 160 0 w 736 128 736 160 0 M 880 120 936 120 0 2.5 w 872 152 888 152 0 w 896 320 864 320 0 w 896 296 896 320 0 w 896 288 864 288 0 w 896 256 864 256 0 w 896 280 896 256 0 152 896 288 944 288 1 3 0.0 150 816 320 864 320 1 2 0.0 150 816 288 864 288 1 2 0.0 150 816 256 864 256 1 2 0.0 154 808 200 872 200 1...
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$ 1 0.000005 5.93429503673921 50 5 43 156 80 352 112 352 0 5 156 256 352 288 352 0 0 156 432 352 464 352 0 5 156 624 352 656 352 0 0 R 48 288 -16 288 1 2 100 2.5 2.5 0 0.5 w 64 288 48 288 0 w 64 288 64 384 0 w 64 384 80 384 0 w 80 288 80 352 0 w 80 352 80 416 0 w 176 352 192 352 0 w 176 416 240 416 0 w 240 416 240 448 0 w 240 448 240 480 0 150 352 464 432 464 0 2 0 w 352 416 352 448 0 w 352 480 240 480 0 w 432 416 432 464 0 w 432 416 416 416 0 w 416 416 416 352 0 w 416 352 432 352 0 w 240 352 256 352 0 w 256 384 224 384 0 w 224 384 224 288 0 w 80 288 80 256 0 w 64 288 224 288 0 w 432 384 432 288 0 w 432 288 224 288 0 w 352 352 352 256 0 w 528 352 528 256 0 150 528 464 608 464 0 2 0 w 528 480 432 480 0 w 432 480 432 464 0 w 528 448 528 416 0 w 608 464 624 464 0 w 624 464 624 416 0 w 624 416 608 416 0 w 608 416 608 352 0 w 608 352 624 352 0 w 624 384 624 288 0 w 624 288 432 288 0 w 720 352 720 256 0 w 528 256 528 240 0 w 192 352 192 256 0...
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docstxt/14458526330588.txt
$ 1 5.0E-6 6.724437240923179 50 5.0 50 193 1083 137 1115 137 0 0.0 193 1083 265 1099 265 0 0.0 193 1083 409 1115 409 0 0.0 193 1083 553 1115 553 0 0.0 w 1083 169 1067 169 0 w 1067 169 1067 297 0 w 1067 297 1083 297 0 w 1067 297 1067 441 0 w 1067 441 1083 441 0 w 1067 441 1067 585 0 w 1067 585 1083 585 0 w 1067 585 1067 665 0 150 859 537 859 441 0 2 0.0 150 875 393 875 313 0 2 0.0 150 891 249 891 169 0 2 0.0 w 843 537 843 553 0 L 843 617 843 697 0 0 false 5.0 0.0 w 859 409 859 393 0 w 875 313 875 265 0 w 875 265 875 249 0 M 1179 137 1227 137 0 2.5 M 1179 265 1227 265 0 2.5 M 1179 409 1227 409 0 2.5 M 1179 553 1227 553 0 2.5 w 891 169 891 153 0 w 843 585 843 617 0 w 843 585 843 569 0 w 843 569 843 553 0 w 859 441 859 425 0 w 859 425 859 409 0 R 1067 665 1067 697 1 2 100.0 2.5 2.5 0.0 0.5 w 843 585 939 585 0 w 1179 553 1179 521 0 w 1179 521 923 521 0 w 923 521 923 537 0 w 923 537 891 537 0 w 1179 409 1179 377 0 w 1179 377 955 377 0 w 955 3...
docstxt/127065420414363.txt
docstxt/133599042936378.txt
$ 3 5.0E-6 10.20027730826997 50 5.0 50 L 648 64 552 64 0 1 false 5.0 0.0 L 648 104 552 104 0 1 false 5.0 0.0 L 648 136 552 136 0 1 false 5.0 0.0 L 648 168 552 168 0 0 false 5.0 0.0 L 648 296 536 296 0 0 false 5.0 0.0 L 648 328 536 328 0 0 false 5.0 0.0 L 648 360 536 360 0 0 false 5.0 0.0 L 648 392 536 392 0 0 false 5.0 0.0 x 505 76 531 82 0 24 a0 x 497 304 524 310 0 24 b0 154 808 72 872 72 1 2 5.0 150 808 112 872 112 1 2 0.0 w 872 288 840 288 0 w 872 264 872 288 0 w 872 256 840 256 0 w 872 224 840 224 0 w 872 248 872 224 0 152 872 256 920 256 1 3 0.0 150 792 288 840 288 1 2 0.0 150 792 256 840 256 1 2 0.0 150 792 224 840 224 1 2 0.0 w 808 80 664 80 0 w 664 88 664 104 0 w 680 64 648 64 0 w 680 64 808 64 0 w 664 104 664 120 0 w 664 120 664 296 0 w 664 296 648 296 0 w 664 120 808 120 0 154 760 160 824 160 1 2 5.0 154 824 168 888 168 1 2 5.0 w 680 72 680 96 0 w 800 96 800 104 0 w 800 104 808 104 0 w 696 104 648 104 0 w 696 104 696 152 0 w 6...
$ 1 5.0E-6 1.0312258501325766 50 5.0 50 L 80 96 48 96 0 0 false 5.0 0.0 150 432 64 512 64 0 2 0.0 150 432 160 512 160 0 2 5.0 150 432 240 512 240 0 2 5.0 150 432 336 512 336 0 2 5.0 150 432 432 512 432 0 2 5.0 152 656 240 736 240 0 5 5.0 w 432 48 144 48 0 w 144 48 144 96 0 w 112 96 112 128 0 I 128 128 192 128 0 0.5 w 144 96 112 96 0 w 112 96 80 96 0 w 128 128 112 128 0 w 432 416 208 416 0 w 432 320 208 320 0 w 432 224 208 224 0 w 192 128 208 128 0 w 208 128 208 224 0 w 208 224 208 320 0 w 208 320 208 416 0 L 112 192 48 192 0 1 false 5.0 0.0 I 128 176 192 176 0 0.5 w 128 176 112 176 0 w 112 176 112 192 0 w 192 176 336 176 0 w 336 176 336 80 0 w 336 80 432 80 0 w 112 192 112 256 0 w 112 256 432 256 0 L 96 320 48 320 0 0 false 5.0 0.0 L 112 400 48 400 0 1 false 5.0 0.0 I 112 320 176 320 0 0.5 w 112 320 96 320 0 w 176 320 176 208 0 w 176 208 352 208 0 w 352 208 352 144 0 w 352 144 432 144 0 w 176 320 176 352 0 w 176 352 432 352 0 w 432 448 ...
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docstxt/132587259117625.txt
$ 1 0.000005 10.20027730826997 50 5 50 L 624 96 624 64 0 0 false 5 0 L 656 96 656 64 0 0 false 5 0 L 688 96 688 64 0 0 false 5 0 L 720 96 720 64 0 0 false 5 0 x 664 47 685 50 4 32 A x 902 48 923 51 4 32 B L 960 96 960 64 0 0 false 5 0 L 928 96 928 64 0 0 false 5 0 L 896 96 896 64 0 0 false 5 0 L 864 96 864 64 0 0 false 5 0 L 1136 16 1104 16 0 0 false 5 0 L 1136 112 1104 112 0 0 false 5 0 I 1152 48 1184 48 0 0.5 5 I 1168 160 1200 160 0 0.5 5 150 1312 48 1360 48 0 2 5 5 150 1312 112 1360 112 0 2 0 5 150 1312 176 1360 176 0 2 0 5 150 1312 240 1360 240 0 2 0 5 w 1296 16 1136 16 0 w 1136 16 1136 48 0 w 1136 48 1152 48 0 w 1312 256 1136 256 0 w 1296 224 1312 224 0 w 1312 192 1200 192 0 w 1200 192 1200 160 0 w 1312 64 1200 64 0 w 1200 64 1200 160 0 w 1312 32 1184 32 0 w 1184 32 1184 48 0 w 1312 96 1184 96 0 w 1184 96 1184 48 0 w 1312 128 1152 128 0 w 1152 128 1152 112 0 w 1152 112 1136 112 0 w 1312 160 1296 160 0 w 1296 224 1296 160 0 w 1296 1...
Some protection to limit the rise time of the ESD pulse should also be added. The release time of the relay also needs to be less than 2.2 ms to be able to "click" at a certain frequency. Flyback protection must also be added. Using Google, you found four possible circuits to use. These four circuits are shown in the below Figure. A B. . C. D. Which circuit will you use that can satisfy all given specifications? Justify your answer. Solution: Specifications state (with circuits adhering in square brackets): ESD protection(high and low swing)[A,C] (B diodes wrong way around, D none) ESD rise time limiting [C] (all others no series resistor) Flyback protection [B,C] (others has none) Release time max 2.2ms [B,C] (others has none, p. 139 table, more than 6V yback) The only circuit that satisfies all specifications is C.
docstxt/14145964572398.txt
$ 3 0.0 21.593987231061412 74 5.0 50 152 936 440 960 440 1 4 0.0 150 904 408 904 424 1 2 0.0 150 904 472 904 456 1 2 0.0 150 872 464 872 448 1 2 0.0 150 872 416 872 432 1 2 0.0 w 904 424 936 424 0 w 872 432 936 432 0 w 872 448 936 448 0 w 904 456 936 456 0 w 904 328 936 328 0 w 872 320 936 320 0 w 872 304 936 304 0 w 904 296 936 296 0 150 872 288 872 304 1 2 0.0 150 872 336 872 320 1 2 0.0 150 904 344 904 328 1 2 0.0 150 904 280 904 296 1 2 0.0 152 936 312 960 312 1 4 0.0 w 904 208 936 208 0 w 872 200 936 200 0 w 872 184 936 184 0 w 904 176 936 176 0 150 872 168 872 184 1 2 0.0 150 872 216 872 200 1 2 0.0 150 904 224 904 208 1 2 0.0 150 904 160 904 176 1 2 0.0 152 936 192 960 192 1 4 0.0 w 904 88 936 88 0 w 872 80 936 80 0 w 872 64 936 64 0 w 904 56 936 56 0 150 872 48 872 64 1 2 0.0 150 872 96 872 80 1 2 0.0 150 904 104 904 88 1 2 0.0 150 904 40 904 56 1 2 0.0 152 936 72 960 72 1 4 0.0 M 984 232 1016 232 0 2.5 M 984 208 1016 208 0 2.5 ...
docstxt/14145957950513.txt
Uamp,V 6,56 6,55 I, A 0,074 0,074 Uout,V 4 3,99 UC,V 2,36 2,36 30 30,52 , s -0,000017 -0,000018 A, dB -1,1 -1,3 Calculations C= 1 µF R= 54 Uout= 4 V f= 5 kHz Us= I Z Conclusion Experimental and calculated results are very similar. The slight difference may be caused by errors in calculations or experimental circuit. 1.3 RLC-Circuit L1 C1 100mH Uout=4V 1uF V1 R1 54 230.16 Vrms 5kHz -89° Figure 3.1: RLC-circuit Figure 3.2: Input and load voltage Figure 3.3: Frequency response Figure 3.4: Frequency response
NOx vähenemine: kuni 50% Tahmasisalduse vähenemine: kuni 10% Süsivesinike (HC) vähenemine Müra vähenemine Vaakum elektriline Väljalaskegaaside jahutussüsteemi lülitamine http://www.youtube.com/watch?v=K0QAvF2PLsY&feature=endscreen EGR Trouble Codes: P0400....Exhaust Gas Recirculation Flow P0401....Exhaust Gas Recirculation Flow Insufficient Detected P0402....Exhaust Gas Recirculation Flow Excessive Detected P0403....Exhaust Gas Recirculation Control Circuit P0404....Exhaust Gas Recirculation Control Circuit Range/Performance P0405....Exhaust Gas Recirculation Sensor 'A' Circuit Low P0406....Exhaust Gas Recirculation Sensor 'A' Circuit High P0407....Exhaust Gas Recirculation Sensor 'B' Circuit Low P0408....Exhaust Gas Recirculation Sensor 'B' Circuit High P0409....Exhaust Gas Recirculation Sensor 'A' Circuit Kü sim us ed ? Aitäh
Student ******* Code ****96 Group AAVB41 Tallinn 2012 2.1. Diode rectifier VD f = 9 kHz U=6V U = 19.7 V R = 96 k Figure 1. Circuit diagram Figure 2. Timing diagram VD + R = 96 k - Figure 3. Replacement circuit Forward biased: Reverse biased: Table 1
Convert the decimal number 43.982 to (a) binary and (b) hex. Show all your calculations. a.) 101011.111110 b.) 2B.FB6 Question 2 Perform the calculation of 58 – 42 by first converting each decimal value to binary and then using the twos complement method. Show all your calculations 5810=001110102 4210=001010102 Converse to twos complement 4210=001010102=110101012+1=110101102 Then 58+(42) 001110102 +110101102 = 000100002 =1610 Question 3 Given the following bridge circuit for a strain gauge, determine the value of the strain gauge resistance {RS}. Let: VIN = 5V R3 = 100 Ω R2 = 50 Ω R1 = 100 Ω 2 Midterm Exam - Solutions a) Under no strain (VOUT = 0 V) b) When VOUT = 0,5 V {under strain}. Solution: a) Under no strain: R1 R3 R1R4 R2 R3 VOUT IN V VIN
microprocessor? b) Explain why this method results in higher resolution. Solution: a) 20 MHz divide by 10000 producing 2000 Hz or time length = 0.5 ms. Number of counts = 0.5ms/100ns=5000 counts 18 MHz divide by 10000 producing 1800 Hz or time length = 0.5555 ms. Number of counts = 0.555ms/100ns=5555 counts The difference is 555 counts. b) Because that the second method has increased the sampling rate. Question 3 (10 marks) Consider the following simple mixer circuit. a) Why do we require a low-pass filter when using this mixer circuit? b) Name another disadvantage of such a mixer circuit. Solution: a) Because the mixer outputs become four (4) including the two input frequencies, the sum and the difference of them. Actually we need only the difference output frequency (Offset – Input) and the lowpass filter will help to filter aways the higher three output frequencies. b) Name another disadvantage of such a mixer circuit (page 97-98)
At breakdown, the diode goes into avalanche where a number of carriers appear suddenly in the depletion layer. With a rectifier diode, breakdown is usually destructive. 4)Typical values: Uknee- approximatly 0.7V; UF 0.7-2.0V; leakage (IR) 1-10 microA/200- 700microA. 5) Idealized characteristic. In view of a very small leakage current in the reverse- bias state and a small voltage drop in the forward-bias state as compared to the operating voltages and currents of a circuit in which the diode is used, the oputput characteristic of the diode can be idealized as shown in the figure. This corner can be used for analyzing the circuit topology, but should not be used for actual circuit design. At turn on, the diode can be considered as an ideal switchbecause it turns on rapidly as compared to transients in the circuit. 6) One of its main applications is in rectifiers, circuits that convert the Alternating voltage or
Estonian Court System Estonia has a three-level court system. Estonian court system consists of four country courts, two administrative courts, three circuit courts and supreme court. Country courts and administrative courts are the courts of first instance, circuit courts are courts of appeal and the supreme court, situated in Tartu, is the court of the highest instance The Supreme Court is also the constitutional review court. In the structure of four country courts(Harju, Pärnu, Tartu and Viru) operate courthouses in every country seat(in Ida- Virumaa and Harjumaa there are three courthouses)In the structure of two administrative courts(in Tallinn and Tartu) there are four courthouses: in Tallinn, Tartu, Jõhvi and Pärnu
A successful attempt followed. A group of eight engineers leaves Shockley Semiconductor to form Fairchild Semiconductors. Kenneth Olsen founds Digital Equipment Corporation. 1958 At Texas Instruments, Jack St. Clair Kilby comes up with the idea of creating a monolithic device (integrated circuit) on a single piece of silicon.Later (in 2000) Kilby receives Nobel price in physics. Jack Kilby completes building the first integrated circuit, containing five components on a piece of germanium half an inch long and thinner than a toothpick. SAGE -- Semi-Automatic Ground Environment -- linked hundreds of radar stations in the United States and Canada in the first large-scale computer communications network. 1959 Fairchild Semiconductor files a patent application for the planar process for manufacturing transistors. The process makes commercial production of transistors possible and leads
Lat Pulls 2x8 Lateral Arm Raises 2x8 Rear- Rear-Delt Flys 2x8 Back Hypers 2x10, add weight if needed Dynamic Bar Twists (low- (low-high- high-low) 2x8 each way 6x100m build- build-ups after lifting Stair Circuit (x6, x3) for time Thursday Wednesday Incline Bench Press (see above) Overheads x6, Underhands x5 w/7.26kg shot Slow Rhythmic Step- Step-ups on 18"
The frequency changes from 20 MHz to 18 MHz and the system samples at an interval of 100ns. a) What is the difference in terms of number of counts detected by the microprocessor? 10 MHz 10 MHz =5000 =5555,555 2000 Hz 1800 Hz Between 20MHz and 18MHz are 555,555 counts. b) Explain why this method results in higher resolution. Higher resolution gained by increased sampling rate. Question 3 Consider the following simple mixer circuit. a) Why do we require a low-pass filter when using this mixer circuit? Mixer needs more parts b) Name another disadvantage of such a mixer circuit. The mixer approach multiplies the frequency shift you want to measure, but also any other frequency shift. This includes drift caused by component heating, noise, etc. Question 4 Consider the following circuit and input waveform. Question 3 Draw an equivalent output waveform. Question 3 Question 5
Department of Electrical Drives and Power Electronics Report on Exercises 2 on Electronics and Semiconductor Engineering Filters Student AAVB-41 Tallinn 2008 Exercise 2.1. Low-pass filter Circuit diagram Timing diagram and frequency responses High-pass filter Circuit diagram Timing diagram and frequency responses Calculations Quantity Calculated Experimental value value Umax, V 14,14 14,14 I, mA 0,0044 0,0044 UR, V 4,47 4,4 UC, V 8,944 8,978
Test Generation name ____________________ 1. Small random circuit Manual test generation matricul. nr. ____________________ (100% coverage) group ____________________ Nr. Random Algorithmic 1 2 3 4 5 6 7 8 9 10 11 12 13 14 2. 8-bit adder Manual test generation Automatic test generation (ATPG)
docstxt/14145960709103.txt
U Smax =U S∗√ 2=11.1∗√ 2=15.7 V PIV =2∗U smax =2∗15.7=31.4 V I max=I d∗√ 2=0.143∗√ 2=0.2 V Table 1. Value comparison table. Parameter Calculated Measured Error Ud, V 10 9.6 0.3 Id, mA 0.143 0.137 0.006 Usmax, V 15.7 15.36 0.54 Imax, mA 0.2 0.22 0.02 PIV, V 31.4 30.2 1.2 Fig. 1 Circuit diagram 2 Peak Inverse Voltage (V) (green) Fig. 2 Peak inverse and output voltage traces Fig. 3 Circuit diagramm II 3 Fig. 4 Output current and voltage traces Conclusions: Learned the about full-wave rectifier working principles and Basic components. Had the chance to build a simple M2 single phase rectifier in the simulation workspace and measure different parameters
Question 1 Name 9 characteristic parameters of sensors. Treshold, noise, range, stability, linearity, accuracy, precision, sensitivity, hysteresis Question 2 Given the circuit below (using a SYH-2R humidity sensor) determine the output voltage for a relative humidity of 70 % at 30 °C if R T = 50 kΩ and VDD= 2.5 V. R70 30 c =R H =9,2 kV RH 9,2 k V O= ∙ V DD= ∙ 2,5 = 0,388 V (R T + R H ) ( 50 k +9,2 k ) Hint: Check specification for Humidity Sensor of SYH-2R.pdf at http://www.rhopointcomponents.com/images/SYH-2R.pdf
and application of electricity, electronics, and electromagnetism Info about electrical engineering This field first became an identifiable occupation in the later half of the 19th century after commercialization of the electric telegraph, the telephone, and electric power distribution and use Subsequently, broadcasting and recording media made electronics part of daily life. The invention of the transistor, and later the integrated circuit, brought down the cost of electronics to the point they can be used in almost any household object. Famous people with big impact are Nikola Tesla, Alexander Graham Bell, john Logie Baird and many more How to become an electrical engineer Electrical engineers typically hold a degree in electrical engineering or electronic engineering. Getting into engineering school takes good grades in math and science. Students also need courses in English, social studies, and computers.
frequency and the input frequency output input · How many thyristors are required for the cycloconverter with the three-phase output 18 · What does the term "a direct ac converter" mean without rectifying without energy storage · What is the most obvious use of the cycloconverter low-frequency · Why does a matrix converter need full controlled devices to change current · Why a device is called as "dc link converter" internal dc circuit · What does the dc link converter consist of rectifier inverter capacitor · What are the applications fields of cycloconverters rolling mills · What does a continuous current means non-pulsing · Call the difference of half-bridge and full-bridge dc/dc converters input/output voltage ratio · Why the transformer-isolated converters are used voltage set-up · Why the back diodes are required current reversing · In the steady state mode, the drive has pulsations ripples
1 9.923 V DC 10M I - DIODE_VIRTUAL 2 Fig. 1 M3 rectifier Circuit diagram Fig. 2 M3 rectifier three-phase input system Output Current (A) (Red) Fig. 3 M3 rectifier output current and voltage traces 3 XSC1
ON ON ON 1 1 1 7 The output voltage is a representation of the switch value. Each additional table entry adds VR/8 to the total voltage. Or, put another way, the output voltage is equal to the binary, numeric value of S0–S2, times VR/8. This 3- switch DAC has 8 possible states and each voltage step is VR/8. We could add another R/2R pair and another switch to the circuit, making a 4-switch circuit with 16 steps of VR/16 volts each. An 8-switch circuit would have 256 steps of VR/256 volts each. Finally, we can replace the mechan- ical switches in the schematic with electronic switches to make a true DAC. Analog-to-Digital Converters The usual method of bringing analog inputs into a microprocessor is to use an analog-to-digital converter (ADC). An ADC accepts an analog input, a voltage or a current, and converts it to a digital word that can be read by a microprocessor. Figure 2
R Uout, V Iout, mA Uout, V Iout, mA 1 28.47 28.47 13.89 13.89 10 28.5 2.85 18.64 1.86 100 28.5 0.29 19.32 0.19 1000 28.5 0.029 19.86 0.02 Fig. 1 AC voltage regulator circuit diagram 2 Fig. 2 Switch AC voltage regulator timing diagram Switch control characteristics graph 30 25 20 15 U(alpha) Uout, V 10 5 0 0 50 100 150 200
31b return to battery- or ground through switch 31c return to battery- 12/24 V relay ELECTRIC MOTORS 32 return 33 main terminal (swap of 32 and 33 is possible) 33a limit 33b field 33f 2. slow rpm 33g 3. slow rpm 33h 4. slow rpm 33L rotation left 33R rotation right TURN INDICATORS 49 flasher unit in 49a flasher unit out, indicator switch in 49b out 2. flasher circuit 49c out 3. flasher circuit C 1st flasher indicator light C2 2nd flasher indicator light C3 3rd flasher indicator light L indicator lights left R indicator lights right L54 lights out, left R54 lights out, right AC GENERATOR 51 DC at rectifiers 51e as 51, with choke coil 59 AC out, rectifier in, light switch 59a charge, rotor out 64 generator control light
12 1100 1 1 14 1110 1 0 15 1111 0 0 Antud tabelist selgub, et leitud MDNK ja MKNK ei ole teineteisega võrdsed. 7. Realiseerida (punktis 3) MDNK-na saadud loogikafunktsioon minimaalseima keerukusega loogikaskeemina, kasutades vabaltvalitud loogikaelemente AND OR ja NOT. Esmalt lihtsustan veidi loogikafunktsiooni tuues 4 sulgude ette: fD = (x2 4) v ( 1 2x3) v (x3 4) 4(x2 v x3) v ( 1 2x3). Loogikaskeemi modelleerin Circuit Simulatoris. Karnaugh kaardi abil kontrollides selgub, et loogikaskeem on õigesti koostatud. 8. Realiseerida (punktis 3) MKNK-na saadud loogikafunktsioon minimaalseima keerukusega loogikaskeemina elementidel AND OR NOT. f K = (x2 v x3)( 2 v 3)( 1 v 4) Loogikaskeemi modelleerin Circuit Simulatoris. Karnaugh kaardi abil kontrollides selgub, et loogikaskeem on õigesti koostatud. 9. Realiseerida (punktis 3) MDNK-na saadud loogikafunktsioon lihtsaima
the loaded induction motor? loaded synchronous motor? The slip frequency 2 of the induction motor depends on the load whereas in the synchronous motor 2 = 0. Test IV What synchronous speeds of AC motors are wrong (at standard supply)? Everything is wrong except 3000, 1500, 1000, 750, 600, 500... Select the impossible values of the AC motor slip: none In the case of three-phase supply, how many phases does the replacement circuit describe? 1 What motor components does the replacement circuit present? stator, rotor What motor parameters does the replacement circuit present? resistance What slip has the maximal value? starting If the voltage drops, how the speed will change? drops (sync. speed will be the same) If the frequency drops, how the speed will change? drops If the slip drops, how will the speed change? increases If the counter-torque drops, how will the speed change? increases If the phase number drops, how will the speed change? no change (ei saa aru kuidas
Department of Electrical Drives and Power Electronics Report on Exercises 1 on Electronics and Semiconductor Engineering Linear Circuits Student AAVB-41 Tallinn 2008 Exercise 1.1. RL circuit Quantity Calculated Experimental value value Umax, V 14,14 14,14 I, mA 983 983 UR, V 9,82 9,81 UL, V 1,85 1,85 -10,7 -10,6 -2,0 -1,7 -0,15 -0,15 Comparative data table Conclusion Calculated and experimental results are very similar. Maximum distinction does not exceed 5 % that may by explained by the simulation errors.
1. N = 0; Z = 0; C = 0; V = 0 2. N = 0; Z = 1; C = 0; V = 0 3. N = 0; Z = 1; C = 1; V = 0 4. N = 1; Z = 0; C = 0; V = 0 5. N = 0; Z = 0; C = 1; V = 0 6. N = 1; Z = 0; C = 1; V = 0 7. N = 1; Z = 0; C = 0; V = 1 8. N = 0; Z = 0; C = 1; V = 1 9. N = 0; Z = 1; C = 1; V = 1 9. a) V and C b) N == Input and output 10. You have four PROM modules like the below figure and a sufficient collection of logic gates. Draw a circuit diagram showing how you can implement 4 kB of MP addressable memory to your Microprocessor with12 address bits. PROM (Programmable Read Only Memory) scheme has 10 address pins == 10. There was an error in the question. Assume the PROM module to be used has only 10 address pins. The input consists of 12 address bits. Use the most significant 2 bits to select a memory chip and the least significant 10 bits to select an address within the chip. The least
the DC motor is used the frequency about 25-30 kHz (avoid noises/discomfort to human). Analyze the advantages and disadvantages of PWM systems: First advantage: This system can reach a very high efficiency without wasted heating loss. Second advantage: This always reaches the full supply voltage, then will produce full opening torque and can overcome easily the internal motor resistances, friction and loads. Third advantage: The PWM circuit is small, cheap, can be used to control a wide range of loads. It doesn’t need expensive variable electronic devices. Main disadvantage: PWM circuit is more complicated with high level of complexity. Second disadvantage: PWM causes vibration frequencies and interferes to other radio signals, to other electronic devices as well as to the human comfort.
Department of Electrical Drives and Power Electronics Report on Electronics and Semiconductor Engineering OP AMPS Student AAAB-41 Tallinn 2011 Exercise 5.1. Non.Inverting Voltage Amplifier Fig . Circuit diagram Fig . Diagrams of bandwidth versus gain. Data table Measur Calculated ed Uin R1, k R2, k KU Uout, V fc, kHz KU Uout, V fc, kHz 0,7 2 18,57 9,63 6,74 146 10,29 7,2 150
Question 1 Name 9 characteristic parameters of sensors. Solution: 1. Thershold. 2. Sensitivity. 3. Full Range. 4. Linearity. 5. Accuracy. 6. Precision. 7. Stability. 8. Hysteresis. 9. Noise. Question 2 Given the circuit below (using a SYH-2R humidity sensor) determine the output voltage for a relative humidity of 70 % at 30 °C if RT = 50 kΩ and VDD= 2.5 V. Solution: Check specification for Humidity Sensor of SYH-2R.pdf at: http://www.rhopointcomponents.com/images/SYH-2R.pdf 2 Week 04 Homework - Solutions Check Thermistor - Wikipedia.pdf at http://en.wikipedia.org/wiki/Thermistor Calculate the Humidity Sensor resistance at 30°C T = 273.15°C +30°C = 303
Tallinn University of Technology Department of Electrical Drives and Power Electronics Report on Exercises 3 on Electronics and Semiconductor Engineering Diode circuits Student AAVB-41 Tallinn 2008 Exercise 3.1. Diode characteristics Fig. 3.1. Circuit diagram Timing diagram Output characteristic (forward bias only) Forward Bias Reverse Bias Umax, V UAC, Vrms Measured Calculated IA, Arms IA, Arms 0,5 0,35 0,006 0 1 0,64 0,1 0
My favorite city , Madrid. GEOGRAPHY Madrid is the capital of Spain. As the capital of Spain, Madrid is also the political, economic and cultural center of Spain. SPORT Madrid is the home to a football club giants Real Madrid. Real Madrid is one of the most prestigious football clubs of the world, having won a record 9 european cups. The City is also the host of the Circuito Permanente Del Jarama, a motorsport race circuit. Madrid hosts the largest bullring in Spain. It was established in 1929. Bullfighting season begins in March and ends in October. WHY DO I LIKE IT? I Chose Madrid for my presentation beacuse, it is a very cultural and a beautiful city.Madrid is also the home for many historical buildings like st. Barbaras curch, Arganzuela and Salamanca. Madrid is the European city with the higest number of trees and green surface. Summers are warm to hot and winters are cold to a bit under the freezing level.
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