y x x·y x2 = s n =8 20,6416 0,0241 0,0617 7,2623E-05 nxy-xy B= A= x 2 y - x y x nx2 -( x )2 nx 2 - ( x ) 2 log paur=f(1/T) 3,000 2,900 f(x) = -1694,2579325841x + 7,6773788319 2,800 R² = 0,9999554742 2,700 2,600 log paur 2,500 2,400 2,300
y = -1642,2x + 7,549 A=7,549 B=-1642,2 b) vähimruutude meetodil; x 2y-xyx A=7,549 A= nx 2- ( x )2 nxy-xy B=-1642,2 B= 0033 0,0034 nx2 -( x )2 2) arvutatakse aine auramissoojus, arvestades, et H aur B=- 2,3 R H aur =-B2,3 R H aur =1642 ,22,38, 3145=31404 , 37 J /mol R = 8,314472(15) J · K-1 · mol-1
ni xini nx2 ni(x- x)2 xi 2 1 2 4 2512,01 6 1 6 36 2127,05 7 1 7 49 2035,81 12 1 12 144 1609,61 17 1 17 289 1233,41 18 4 72 1296 4656,70 20 1 20 400 1031,69 22 1 22 484 907,21 27 2 54 1458 1262,03 29 1 29 841 534,53 31 1 31 961 446,05 34 1 34 1156 328,33 ...
cn −1 0 0 √ 1/ n 4 1 1 Z 1 − nx2 dx = √ > √ . >2 0 3 n n Edasi, kui 0 < δ < 1, siis √ n δ 6 x 6 1 ⇒ 0 6 Qn (x) 6 n 1 − δ2 , (6.35)
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