Süsteemiteooria kogu 2009
2 - 2 2 2 -1 2 6 - 6 6
1 -1 1
( A - 1 E )( A - 2 E ) 1 1 0 1 1 1 6 - 6 6
i = 3, z3i = = = = 1 -1 1
(3 - 1 )(3 - 2 ) ( -1 + 3)(-1 + 4) 6
1 -1 1
Vastus
n
e At = zi1e t =
i =1
1 -2 1 -1 3 -2 1 -1 1
- 3t -4t -t
=e -1 2 -1 + e 0 0 0 + e 1 -1 1
-2 4 -2 1 -3 2 1 -1 1
Nagu näha, saime kahel meetodil samad tulemused.