"tagasiasendusega" - 1 õppematerjal

Lembit Pallase materjalid

Seega (x - 1)dx 2 2 = 2 - 2 dt (x + 1) 1 - x2 t t +1 2 = - - 2 arctan t + C. t 1 - x2 1 - x2 Tagasiasendusega t = =- saame x-1 1-x (x - 1)dx 2(1 - x) 1 - x2 = + 2 arctan +C (x + 1) 1 - x2 1 - x2 1-x 1-x 1+x =2 + 2 arctan + C.