Muutuja vahetusest 2+x3 = x3 t3 , millest (2+x3 ) 3 = x2 t2 ja 2 2 2 4t2 x4 (2 + x3 ) 3 = x6 t2 = 3 t2 = 3 . t -1 (t - 1)2 Asendades lugeja ja nimetaja, leiame 2 dx - (t2t3 -1) dt 2 1 = 4t2 =- dt x2 (2 + x3 )2/3 (t3 -1)2 2