"realisatsioon2" - 1 õppematerjal

Eksamiülesande lahenduse aruanne

.. 1 1 1 1 1 ... 0 0 0 0 0 ]'; cover_all = [cover, cover, cover, cover, cover, cover, cover, cover, cover, cover,... cover, cover, cover, cover, cover, cover, cover, cover, cover, cover, cover,... cover, cover, cover]; 14 Realisatsioon1: test_data=greek_alphabet.*cover_all test=sim(net,test_data) for i=1:24 m=max(test(:,i)); test_result(i)=find(test(:,i)==m) end Realisatsioon2: test_data2=greek_alphabet.*cover_all t=sim(net_c,test_data2); test_out=vec2ind(t) Selline olukord annab juba üsna vigaseid tulemusi mõlema lahenduskäigu puhul. Katame ühe nurga: cover = [1 1 1 1 1 ... 1 1 1 1 1 ... 1 1 1 1 1 ... 1 1 1 1 1 ... 1 1 1 1 0 ... 1 1 1 0 0 ... 1 1 0 0 0 ]'; jne sama tegevuskäik mis enne.