Soojusvaheti
5 55 986,78 0,53*10 0,6499 3,4 0,252 6380,9 31,4 1504,8
-3
0 9
· hk
t=(42+12)/2=27 oC; =996,35 kg/m3;=0,855*10-3Pa*s; k=0,6114 W/m*K; Pr= 5,85
u=0,057kg/s/(996,35kg/m3*0,000145 m2)=0,395 m/s
Re=Dsise*u*/=0,0136m*0,395(m/s)*996,35(kg/m3)/0,000855m2= 6260
Kuna 2300 < Re <10000, siis kasutame Nu arvu leidmiseks 4.1.graafikut
Pavlov, Romankov, Novkovi raamatust.
Nu/Pr,0,43*(Pr/Prsein)0,25= 21
13
14
Nu= 5,850,43*(5,85/5,52)0,25*21=45,54
hkülm= Nu*k/Dsise= 45,54* 0,6114 W/m*K/(0,0136m)= 2047,3W/(m2*K)
Ukats=1/(1/hsoe+1/külm+/+rsaast)= 1/ [1/3053,45 W/(m2*K) + 1/2047,3 W/(m2*K)
+0,0012m/109 W/(m*K)+0,0003 m2*K/W]= 887,35 W/(m2*K)
U
a