Keemia materjaliõpetus ja ( vene keeles )
[H+]=a*Cm=0.05*0.0025=1.25*10-4mol/l
G = H TS => G = 0 => T = H/S pH= -log[H+]=-log(1.25*10-4) = 3.9 <7
12. .
(S>0) 0.00055M NaOH
. , , , [OH-]=Cm=0.00055mol/l
( ), . , [H+]=KH2O/[OH-]=1*10-14 /0.00055 = 1.8*10-11 mol/l
( ) . (S<0) pH= -log[H+]=-log(1.8*10-11) = 10.7 >7
, , , 24. (2) = 1,86 (2) = 0,516
. 1 v=i=1 i=1+a*(v-1)
13. G. t = 950 ? 2 NaCl (=100%) i= 1+1.0*(2-1)=2
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