HCl lahus
mol
3) Calculation of the systematic error for the experiment:
result C M ,solution no .2 −actual C M , solution no.2
∆= ×100
actual C M , solution no .2
0, 05 M −0, 0565 M
∆= × 100 =9,12
0, 0565 M
Conclution
Using titration we can calculate the consentrations of incredients (acid/base). Through this experiment
I got the molar concentration. Systematic error of this experiment is 9,12%. As it is less than 10% we
can consider it OK. To decrease the systematic error I should monitor more closely the titration
process and read results more punctually.