"c8h10" - 1 õppematerjal

Aururõhu praktikum

5) 80 juures (353,15K) 1236,991 = - = 4,43126 - = 10-0,484809 = 0,327485 = 32,75 + 353,15 + (-101,528) 6) 90 juures (363,15K) 1236,991 = - = 4,43126 - = 10-0,296901 = 0,504776 = 50,48 + 363,15 + (-101,528) Leian moolimurru mõlemale ainele: Etüülbenseeni moolide arv: M(C8H10)= 12*8+10*1 = 106 g/mol  17,7558 g n(C8H10)= = = 0,168 106 / Isobutanooli moolide arv: M(C4H10O) = 12*4+ 1*10+16 = 74 g/mol 19,5579 g n(C4H10O) = = = 0,264 74 / 0,168 Etüülbenseeni moolimurd: 1 = 0,168 mol+0,264 mol = 0,39 0,264 Isobutanooli moolimurd: 2 = = 0,61 0,432mol