Lineaaralgebra eksam
.., in) jaoks on üks
liidetav (-1)(i1, i2, ..., in)a1i1a2i2...anin
detA = |A| = = (i1, i2, ..., in) Sn (-1)(i1, i2, ..., in)a1i1a2i2...anin
Teist järku determinant: detA = (i1, i2) Sn (-1)(i1, i2)a1i1a2i2 = (-1)(1, 2)a11a22 + (-
1)(2, 1)a12a21 = a11a22 - a12a21
Kolmandat järku determinant: detA = (i1, i2, i3) Sn (-1)(i1, i2, i3)a1i1a2i2a3i3 = (-1)(1, 2,
3)
a11a22a33 + (-1)(1, 3, 2)a11a23a32 + (-1)(2, 1, 3)a12a21a33 + (-1)(2, 3, 1)a12a23a31 + (-1)(3,
1, 2)
a13a21a32 + (-1)(3, 2, 1)a13a22a31 = a11a22a33 - a11a23a32 - a12a21a33 + a12a23a31 +
a13a21a32 + a13a22a31
Sarruss'i reegel - skeem kolmandat järku determinandi leidmiseks
14. Crameri valemid ja nende tõestus juhul n = 2.
x1 = D1/D; x2 = D2/D; ...; xn = Dn/D, kus Dj on determinant, mis tekib
determinandist D, kui seal j veerg asendada vabaliikmete veeruga b 1, b2, ...,
bn
Nõuded: võrrandite arv = tundmatute arv; D 0