"580mpa" - 1 õppematerjal

Reduktori projekt

 4 10 6 Väikesel hammasrattal K FL 2 = 6 N1 Valin KFL1 = 1 Arvutan lubatud kontaktpinged a) Suurrattal [ ] H 2 = K H 2 [ H 02 ] = 1 519 = 519 MPa , kus [ H 02 ] = 1,8 HBmed 2 + 6 = 1,8 251 + 67 = 519 MPa b) Väikerattal [ ] H1 = K H1 [ H 01 ] = 1 580 = 580 MPa , kus [ H 01 ] = 1,8 HBmed 1 + 6 = 1,8 285 + 67 = 580MPa Arvutan lubatud paindepinged [1 lk.11] Suurel hammasrattal N [ ] F = K F2 [ ] F 02 = 1 258 = 258 , kus 2 mm 2 [ ] F 02 = 1,03 HBmed 2 = 1,03 251 = 258 N 2 mm Väikesel hammasrattal [ ] F1 = K F1 [ ] F 01 = 1 293 = 293 N 2 , kus mm [ ] F 01 = 1,03 HBmed1 = 1,03 285 = 293 N 2 mm