Ltr =Ltöö+Lä+L0+Lvaru Ltr Ltöö = Ztöö*t; Ztöö= π∗Dtr ; Ltr=H*ipol 22000∗4 Ltöö = 3,14∗500 ∗22=1233 mm Lä =Zä*t; Lä =2,5*22=55 mm 3 L0=Z0*t; L0 =5*22=110 mm Lvaru=L0=110 mm Ltr =1233+55+110+110=1508 mm. 2.4. Trumli tugevusarvutus Ltr ≥ 3Dtr √ Mp2+T 2 δ= ω ≤ [δ] Dtr T =Smax* 2 ; T =38,65*250=19325 kN*mm. Smax 38.65 ∗Ltr ∗2079 2 ; Mp= 2 Mp = =20088 kN∗mm . 2 2 Dtr 4−Dts 4 ω = 0,1* Dtr ; Dtr =500 mm Dts = Dtr - 2δ; Dts =500-2*20=460 mm 500 4−4604 ω = 0,1* 500 = 35,5*10^5 MPa √200882 +193252 δ= 35,5∗10 5 =78,52*10^6 MPa ≤ [δ] 2.5
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