"16520g" - 1 õppematerjal

Harjutustund 2 vastused

Segu üldruumala = 123,2L + 201,6L + 23,97L + 16,8L = 365,57L %(He)V = (123,2L/365,57L)*100% = 33,7% %(H2)V = (201,6L/365,57L)*100% = 55,1% %(N2)V = (23,97L/365,57L)*100% = 6,6% %(Ar)V = (16,8L/365,57L)*100% = 4,6% 1 3. Mitu liitrit SO2 temperatuuril 35 oC ja rõhul 110,5 kPa on vaja 25 kg 65%-lise H2SO4 saamiseks, kui protsessi saagis 87%? Lahendus: SO2 H2SO4 m(H2SO4) = 25000g*0,65 = 16520g n(H2SO4) = 16520g/98g/mol = 165,8mol n(SO2)saagise 87% arvestades= 165,8mol*100%/87% = 190,6mol P = 110500Pa, T=(35+273) = 308K, n=190,6mol, R=8,314Pa*m3*K-1*mol-1: P a *m 3 1 9 0 ,6 m o l* 8 ,3 1 4 *3 0 8 K n *R *T m o l* K V (S O 2 ) = = = 4 ,4 1 7 m 3 = 4 4 1 7 L