Diskreetne matemaatika I IAY0010 kodutöö
f =x 1 x 2 f ( 11 x3 x 4 ) V x´ 1 x2 f ( 01 x 3 x 4 ) V x 1 ´x 2 f (10 x 3 x 4 )V ´x 1 x´ 2 f ( 00 x 3 x 4) =
= x 1 x 2 ( 0∗0∗´x 4 V 1∗x 4 V 1∗x 3 ) V x 1 ´x 2 ( 0∗1∗´x 4 V 1∗x 4 V 1∗x 3 ) V
V x´ 1 x2 ( 1∗0∗´x 4 V 0∗x 4 V 0∗x 3 ) V ´x 1 ´x 2 ( 1∗1∗´x 4 V 0∗x 4 V 0∗x 3 ) =
= xx 1 x 2 ( x 3 V x 4 ) V x´ 1 x 2 ( 0 ) V x 1 ´x 2 ( x 3 V x 4 ) V ´x 1 ´x 2 ( x´ 4 ) =
3
= xx41 x 2 ( x 3 V x 4 ) V x 1 x´ 2 ( x 3 V x 4 ) V ´x 1 ´x 2 ( x´ 4 )
´x 1 ´x 2 ´x 4 V x1 x 4 V x 1 x 3
9) MDNK =
Konjunktiivne arendus : Võtan kaheks muutujaks x 1 ja x2
f =[ x 1 V x 2 Vf ( 00 x3 x 4 ) ]∗[ x 1 V ´x 2 Vf ( 01 x 3 x 4 ) ]∗[ ´x 1 V x2 Vf ( 12 x 3 x 4 ) ]∗[ x´ 1 V ´x 2 Vf ( 11 x 3 x 4 ) ] =
[ x 1 V x 2 V ( 1∗1∗´x 4 V 0∗x 4 V 0∗x 3 ) ] ∧¿