"x2x3xx" - 1 õppematerjal

DISKMAT KODUTÖÖ 2015

1 0 1 0 1 1 f = (x1 v x3)(x2 v x3 v x4)(xx 1 v xx 3 v xx 4) = (x1x2 v x1x3 1 0 1 1 0 0 v x1x4 v x2x3 v x3x3 v x3x4)(xx 1 v xx 3 v xx 4) = x1x2xx 1 v 1 1 0 0 1 1 x1x2xx 3 v x1x2xx 4 v x1x3xx 1 v x1x3xx 3 v x1x3xx 4 v x1x4xx 1 1 1 0 1 1 1 v x1x4xx 3 v x1x4xx 4 v x2x3xx 1 v x2x3xx 3 v x2x3xx 4 v x3xx 1 v x3xx 3 v x3xx 4 v x3x4xx 1 v x3x4xx 3 v x3x4xx 4 = x1x2xx 3 v 1 1 1 0 1 1 x1x2xx 4 v x1x4xx 3 v xx 1x3 v x3xx 4 1 1 1 1 0 0 Saadud DNK: f = x1x2xx 3 v x1x2xx 4 v x1x4xx 3 v xx 1x3 v x3xx 4