"ts0298" - 1 õppematerjal

Kodutöö II. Siseeneergia

kJ/mol = -41170 J/mol S0298 = S0298(H2) + S0298(CO2) - S0298(H2O) - S0298(CO) = 130,52 + 213,66 ­ 188,72 ­ 197,55 = -42,09 J/mol*K G0298 = -41170 ­ 298*(-42,09) = -28627,18 J/mol = -28,62718 kJ/mol -G/RT 2. Kp = e Kp = e28627,18/(8,314 * 298) = 1,0425*105 3. T M0 M1*10-3 M2*105 1400 0,7595 0,4336 0,34835 G0T = H0298 - TS0298 ­ T(aM0 + bM1 + cM2) G01400 = -41170 J/mol ­ 1400K * (-42,09 J/mol*K) ­ 1400K * [ (27,28 + 44,14 ­ 30,00 ­ 28,41)*0,7595 + (3,26 + 9,04 ­ 10,71 ­ 4,10)*10 -3*0,4336*103 + (0,5 - 8,54 + 0,33 + 0,46)*105*0,34835*10-5 ] = 8981,8899J/mol = 8,98 kJ/mol 4. Aine Lähteaine Reageeris Tekkis Tasakaal Moole Moolimurd CO 1 x - 1­x 1 ­ 0,4 = 0,6 0,6/2 = 0,3