TAANDAMISVALEMID X-TELJEST I veerand II veerandist I veerandisse Sin(90®-α)=cosα Sin(180®-α)=sin α Cos(90®-α)=sinα Cos(180®- α)= -cosα Tan(90®-α)=cotα Tan(180®-α)= -tanα Sin(π/2-α)=cosα Cot(180®-α)= - cotα Cos(π/2-α)=sinα Sin(π- α)=sin α Tan(π/2-α)=cotα Cos(π- α)= - cos α Tan(π- α)= -tan α II veerandist I veerandisse Cot(π- α)= -cot α Sin(90®+α)=cosα Cos(90®+α)= -sinα III veerandist I veerandisse Tan(90®+α)= -cotα Sin(180®+ α)= -sin α Sin(π/2+α)=cosα Cos(180®+α)= -cosα Cos(π/2+α)= -sinα Tan(180®+α)= tanα Tan(π/2+α)= -cotα Cot(180®+α)=cotα Sin(π+α)= -sinα III veerandist I veerandisse Cos(π+α)= - cosα Sin(270®-α)= -cosα Tan(π+α)=tanα Cos(270®-α)= -sinα Cot(π+α)=cotα Tan(270®-α)=cotα Sin...
b = 5 cm c = 10 cm -Ja kui alpha kraadi on vaja leida cos A' = b/c = 5/10 = 0.5 A' = arccos(0.5) = 60 radtodeg(arccos(0.5))=60' ------------------------------------------------ a = 5 cm c = 7.86 cm -Kui on vaja leida beeta kraadi cos B' = a/c = 5/7.86 = 0.636.. B' = arccos(0.636) = 50.495.. radtodeg(arccos(0.3)) = 50'29' Tanges: tan = vastaskülg / lähiskülg Nagu näha ei ole tanges seotud kolmnurga kõige pikema külje hüpotenuusiga(c). GM-is näeb tangesega nurga arutamine välja nii: //kraadideks(tangese_pöörd_tehe(suhte_valem)) radtodeg(arctan(vastaskülg / lähiskülg)) tangese kasutamine nii alfa kui ka beeta kraadi leidmisel: a = 2.5 cm b = 4 cm -Ja kui alpha kraadi on vaja leida cos A' = a/b = 2.5/4 = 0.625 A' = arctan(0.625) = 32.994.. radtodeg(arctan(0.5)) = 32'
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