"sekudaarparameetrid" - 1 õppematerjal

Homogeene liin

14=3768 I ' 2 =I 2∗eiψ 2=52,1∗10−3∗e 12,42 j=52,1∗10−3∗( cos 12.42+ jsin 12.42 )=0.051+ j 0.011=0.052∠ 12.17 −3 0 Z 0 =R 0 +ω∗L0∗ j=5.5+3768∗3∗10 j=5.5+ j 11.3=12,57 ∠ 64,05 −6 −9 −6 −5 0 Y 0=G 0 +ω∗C 0∗ j=0.65∗10 +3768∗10∗10 ∗j=( 0.65+ j 37.68 )∗10 =3,77∗10 ∠ 89,01 Sekudaarparameetrid: ZC = √ √ Z0 Y0 = 5.5+ j11.3 ( 0.65+ j 37.68 )∗10−6 =1000∗ √ 5.5+ j 11.3 0.65+ j37.68 =1000∗ √