H0298 = Hf(H2) + Hf(CO2) - Hf(H2O) - Hf(CO) = -393,51 + 241,81 + 110,53 = -41,17 kJ/mol = -41170 J/mol S0298 = S0298(H2) + S0298(CO2) - S0298(H2O) - S0298(CO) = 130,52 + 213,66  188,72  197,55 = -42,09 J/mol*K G0298 = -41170  298*(-42,09) = -28627,18 J/mol = -28,62718 kJ/mol -G/RT 2. Kp = e Kp = e28627,18/(8,314 * 298) = 1,0425*105 3. T M0 M1*10-3 M2*105 1400 0,7595 0,4336 0,34835 G0T = H0298 - TS0298  T(aM0 + bM1 + cM2) G01400 = -41170 J/mol  1400K * (-42,09 J/mol*K)  1400K * [ (27,28 + 44,14  30,00  28,41)*0,7595 + (3,26 + 9,04  10,71  4,10)*10 -3*0,4336*103 + (0,5 - 8,54 + 0,33 + 0,46)*105*0,34835*10-5 ] = 8981,8899J/mol = 8,98 kJ/mol 4. Aine Lähteaine Reageeris Tekkis Tasakaal Moole Moolimurd CO 1 x - 1Âx 1  0,4 = 0,6 0,6/2 = 0,3
= 239,76  197,55  2*130,52 = -218,83 J/K*mol G0298 = -90470  298 * (-218,83) = -25258,66 J/mol = -25 kJ/mol - G 2) Kp = e RT Kp = e 25258,66 ¿/8,314298 = 2,7 * 104 3) Tasakaalu konstandi leidmine T = 400 K juures T M0 M1 *10-3 M2 * 10-6 M-2*105 400 0,0392 0,0130 0,0043 0,0364 G0T = H0298  298*S0298 - T (a * M0 + b * M1 + c * M2 + c` * M-2) G0400 = -90470  400 *(-218,83)Â400 * [(15,28-28,41-2*27,28)*0,0392+(105,20-4,10- 2*3,26)* 103*0,0130*10-3+(-31,04)*106*0,0043*10-6+(0,46-2*0,50)*10-5*0,0364*105]= =-90470  400 *(-218,83)Â400*(-1,6105)= -2336,28 J/mol = -2,3 kJ/mol 112824 Kp = e =2,018 8,314400 4) Tasakaalulise gaasisegu koostise arvutamine temperatuuril T ja rõhul P
annaabi.ee 
