Temparature C Mechatronics Systems in Automotive Engineering 6 Week 04 Homework - Solutions % Matlab drawing graphic program OK X = [-10 0 10 20 25 30 40 50 ]; Y = [44.6 28.1 18.2 12.1 10 8.27 6.4 5.7]; X0 = 0; n = 100; f = 0.1; x = linspace(min(X),max(X),n); y = interp1(X,Y,x,'spline'); xt = X0+(0.1*(max(X)-min(X))*[-1 0 1]); m = diff(y)./diff(x); m = [m, m(end)]; % so just add one at the end k = min([find(x >= X0,1,'first'), length(x)]); yt = y(k) + m(k)*(0.1*(max(X)-min(X))*[-1 0 1]); plot(X,Y,'ro', x,y,'-b',xt,yt,'--g'); xlabel('Temparature ^0C'); ylabel('Thermistor resistance R_{th} (ohm)'); b) Assume VR = 5V. You are designing for a measurement accuracy of ±0.5°C. Formular to calculate the self-heating dissipation P: where, D.C.=Dissipation Constant=1mw/°C, Required accuracy = ±0.5°C P=1mw/°C*0.5°C=0.5mw.
4 Failiga seotud grupp root 5 Faili suurus 3.8M 6 Faili viimane muutmise aeg Dec 11 16:36 7 Faili nimi System.map-4.4.0-104-generic Ülesanne 2 Kopeeri kataloog /etc koos alamkataloogidega kataloogiks /var/backups/etc-copy , nii et säiliksid kataloogi ja failide omanikud ja ajatemplid. Kontrolli korraldusega diff , kas kataloogid /etc ja /var/backups/etc-copy on identse sisuga. Käsk cp (copy) kopeerib faile ja katalooge. Lipuga -d ei järgita sümboolseid viitasid kopeeritavas kataloogis. Lipuga -R (recursive) kopeeritakse kataloogi sisu rekursiivselt ehk kopeeritakse kõik kataloogis olevad alamkataloogid koos nendes sisalduvate failidega. Lipuga -v (verbose) näeme detailset informatsiooni käsu täitmise kohta.
= võtab eksaktruse tingimus kuju y x ja see on samaväärne seosega µ µ N M M- N = µ - y x x y Oleme saanud esimest järku osatuletisega võrrandi µ ( x, y ) suhtes. Integreeruvusteguri leidmiseks peaks lahendama selle võrrandi. Lahendi sileduse teoreem vaatleme võrrandit y`=f(x,y). olgu f F(x,y) k korda pidevalt diff-uv piirkonnas D. Siis DV y`=f(x,y) iga lahend on k+1 korda pidevalt diff-uv.
Variable Rest Hard exercise Alveolar ventilation (l/min) 4.2 140 Tidal volume (l) 0.5 3 Breathing rate 12 55 (per min) Expired ventilation (l/min) 6 180 O2 consumption (ml/kg/min) 3.5 85 Alveolar PO2 (mmHg) 100 120 Arterial PO2 (mmHg) 97 90 (A-a)PO2 diff. (mmHg) 2-10 30 Mixed venous PO2 (mmHg) 46 20 Arterial PCO2 (mmHg) 40 25-32 Arterial pH 7.4 7.2-7.3 Pulmonary blood flow (l/min) 5 30 Lung capillary blood volume 70 250 (ml) Mean red blood cell transit 0.75 0.5 time (s) in Martin & Coe (1997) pp119
In the lungs: HCO3- + H+ H2CO3 H2O + CO2 Gas Exchange at the Muscles - a-vO2 Difference Rest This describes the extent to which O2 is extracted, or removed, from the blood as it passes through the body. An increased a-vO2 difference represents a decreased amount of oxygen in venous blood. Arterial-Venous Oxygen Difference The Fick equation represents the relationship of the body's oxygen consumption (VO2), to the arterial-venous oxygen difference (a-vO 2 diff) and cardiac output (Q); VO2 = Q x (a-vO2 diff) Rest 4 to 5 ml/100 ml blood Intense exercise - 15-16 ml/100 ml blood Oxygen Transport in Muscles O2 transported to mitochondria by myoglobin (similar to Hb but a greater affinity to O2) Factors affecting O2 delivery and Uptake O2 content of blood Blood flow Local conditions (e.g. pH, temp) Recommended Reading Baechle, T. R., Earle, R.W. (eds) (2008) Essentials of strength training and conditioning .
tempf=fact(factorial); array[var]=pow(X,factorial)/tempf; if (fabs(array[var]-array[var-1])>=e) { flag=var+1; printf("Max difference limits is reached!n"); break; } factorial+=2; flag=var+1; } printf("Defenition done!n"); } void printData() { FILE*pFile; pFile = fopen ("myfile.txt","w"); fprintf(pFile,"%2c%c%8s%c%8sn",35,124,"array",124,"diff"); for (int i = 1; i < flag+1; i++) { fprintf(pFile,"%2d%c%8f%c%fn",i,124,array[i- 1],124,fabs(array[i-1]-array[i-2])); } fprintf(pFile,"Total number of elements %dn", flag); fclose(pFile); free(array); } int fact(int n) { if ( n <= 1 ) return 1; else return n * fact(n-1); }
x→ a x−a x→ a x−a dy Avaldis f’(x)∆x nim. y=f(x) differentsiaaliks(esimene järk: dy või df). dy = df = f’(x)∆x dy = f’(x)∆x ↔ f’(x) = dx Diff. omadused: Funktsiooni diferentsiaal on võrdeline argumendi muuduga. Nullist erineva tuletise korral on funktsiooni muut dy f ekvivalentne funktsiooni diferentsiaaliga piirprotsessi ∆ x→0 . f’(x) = . D(f+g) = df + dg. d(f*g) =df*g + f*dg. d( )=
amplification.DISADVANTAGES:high noise and limited frequency range, over which the stabilization is effective.Phase delay.DC stops.Additional area, volume, size, weight of amplifiers. 8) If Vrms = 10, then Vpeak-to-peak sin is approx. equal to: 10 30 60 90 What is the current gain with an input current of 5A and an output current of 10mA? 2 50 2000 5000 Ticket No8 1)Differential amplifier, or diff amp circuit.2) 3)Figure presents a general form of a diff amp that is termed a long-tailed pair because R E is called a tail resistor.It has two inputs:U1 and U2.Because there are no coupling or bypass capacitors, the input signals can have frequencies all the way down to zero, equivalent to dc, and the amplifier has a broad midband and high stability.The output signal is the voltage on the load connected between the collectors.Ideally, the circuit is symmetrical with identical
most survived the war. Factory owners, bank managers, large shopowners, ideological enemies. Also religious enemies, rabbis, cultural leaders, writers. Another group rounded up were refugees from Germ-occupied Poland, tens of thousands of mostly young Js. Couldn't go S, Czechoslovakia annexed, Romania fascist and anti-Semitic, sea lanes closed, mostly E. SU identifies as suspect, could be a spy. J identity very different from SU J, more use of Yiddish, more traditional, state of mind diff. Germs had dumped Js on the border, green border policy. Registered as they came over the border, porous. 6 mill SU citizens deported internally, 1920-1952, policy for suspect groups. What about everybody else? Sovietization mostly on urban centers, more keenly felt than on periphery. Farmers in Bessarabia, barely felt Sovietization, have a talk, mainly to get wine, gratice. 60,000 Polish Js removed, 39-41. 150,000 Js from annexed territories arrive in unoccupied parts. Birobidzhan
Monteeri see ajutisse asukohta ja kopeeri kogu /var/www . Kontrolli, et sisud on identsed. Monteerime sda3 ajutisse monteerimispunkti /mnt ja määrame lipuga -t failisüsteemi tüübiks ext4 . student@server:~$ sudo mount -t ext4 /dev/sda3 /mnt Kopeerime /var/www sisu /mnt sisuks lipuga -a : rekursiivselt ja jättes muutmata kõik atribuudid. student@server:~$ sudo cp -a /var/www/* /mnt Kontrollime sisu erinevusi käsklusega diff . Erinevusi ei ole. student@server:~$ sudo diff -rq /var/www /mnt/www Kustuta /var/www sisu ja monteeri uus failisüsteem /var/www alla. Kustutame /var/www sisu, jättes kataloogi alles. student@server:~$ sudo rm -r /var/www/* Monteerime uue failisüsteemi /var/www alla. student@server:~$ sudo mount -t ext4 /mnt /var/www Veebibrauseris serveri kohtvõrgu aadressil on näha veebilehte.
MMD-tekitab uue dos-i kataloogi MMOVE-nimetab ühe faili nime ümber mingiks teiseks faili nimeks MRD-kustutab dos-i katalooge MREN-nimetab dos-i faili ümber MTYPE-trükib dos-i faili sisu ekraanile MZIP-spetsiaalsed zip-ketta käsud XCOPY-kopeerib dos-i katalooge CHMOD-muudab failide juurdepääsulubasid CHOWN-muudab failide omanikku ja kasutajate gruppi DV-arvutab kasutatud ketta ruumi DF-arvutab ketta vaba ruumi FIND-leia LOCATE-trükib ekraanile mingi faili asukoha mida otsid DIFF-tekstifailide võrdlemine CMP-võrdleb faile CAT-trükib faili sisu ekraanile CPIO-kopeerib failid kettale või teise kohta lokaalmasinas DD-muudab faile kopeerimise ajal FILE-uurib järele mis tüüpi fail on Arvutivõrgud Arvutivõrk on arvuteid ühendav kaabeldus. Olemas on hästi palju erinevaid arvutivõrke : Erinevaid võrgutüüpe nimetatakse võrgutopoloogiateks (ik-network tophology).
It is folk etmymology. It happenes to borrowed words most often (nt, french etiquette quite the ticket, meaning proper, polite). To understand the mot of a word, we must know its history . 5. Morphemes, allomorphs. Types of morphemic segnetability. Morphemes are the smallest lexical units (can not divide). They make up words. Morphemes have a certain meaning. (nt, pre preplain, preview; less waterless; hood brotherhood). Some morphemes have diff sounds(nt, please, pleasure, pleasant). They are variants of the same morpheme or allomorph. Types: segmentable those we can divide into morphemes (nt, hero- ic; happy ness). Non- segmentable- cannot divide any further (nt, luck, hand, smile). Types of morphemic segmantability: a)complete segm occurs in words with transparent structure (läbinähtav), (nt, south- ern; mis-manage) b)conditional segm characterizes words whose division is doubtful for semantic resons(nt, recieve, decieve)
Pp nn 0 = t ln = t ln Pn np t - temperatuuripotentsiaal t 25mV k 1,38·10-23 Boltzmanni [J/K] - konstant q laengukandja laeng Jdif - diff. voolu tihedus Jtr - triivivoolu tihedus Jdif = Jtr kT t = q 24 Pingestame pärisuunas! Ruumiliste laengute Q vähenemine P-n siirde laiuse vähe-
testing. In most environments, acceptance testing by the system provider is distinguished from acceptance testing by the customer (the user or client) prior to accepting transfer of ownership. In such environments, acceptance testing performed by the customer is known as beta testing, user acceptance testing (UAT), end user testing, site (acceptance) testing, or field (acceptance) testing. 59. Configuration Management. -managing the products of system change (for different machines,offering diff. Funcktionality); is concerned with managing evolving software systems (system change=team activity,CM aims to control the costs and effort in making changes),involves the development and application of procedures. CM standarts – CM should be based on a set of standarts that r applied within an organization and should define how items r identified,how changes r controlled and how new versions r managed.
2.MM võrrandi tuletamine statsionaarse faasi eeldused Kiire tasakaalu eeldus sai väga palju kriitikat, pole õigustatud. Briggs ja Haldane pakkusid välja üldisema lahenduse, ei teinud kiire tasakaalu eeldust. Nad ei teinud eeldusi üksikute kiiruskonstantide väärtuste kohta. Reaktsiooniskeem on ikka kaheastmeline (k1 on teist järku kiiruskonstant, k-1 ja k2 on esimest järku) Juurde toob ainult üks nool, + märgiga seega k1. Ära viivad kaks noolt, mõlemad tuleb maha lahutada. Diff võrrandist lahti saamiseks on hea eeldada, et [ES] ajas ei muutu, seega see on statsionaarse faasi eeldus. Väitsid, et eksisteerib olukord, kus ensüüm-substraat kompleksi konts ajas ei muutu, sest 13 teda juurde toovate ja ära viivate radade summarsed kiirused on võrdsed. Statsionaarne olek juurde toovate ja ära viivate radade summaarsed kiirused on võrdsed
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