Harjutustund 3 Õhu niiskus
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m(suhkur) = 302400g*0,015 = 4536g
m(suhkru 30%-line lahus) = 4536g/0,3 = 15120g
m(H2O) = 302400g - 15120g = 287280g = 287kg = 287L
7. Mitu liitrit gaasilist HCl (n.t.) ja vett on vaja 8 dm3 2M vesilahuse (=1,06g/cm3)
valmistamiseks?
Lahendus:
n(HCl) = c*V = 2mol/L*8L = 16mol
V(HCl) = n*Vm = 16mol*22,4L/mol = 358L
m(HCl)2M lahus = *V = 1,06g/cm3*8000cm3 = 8480g
m(HCl) = n*M = 16mol*36,5g/mol = 584g
m(H2O) = 8480g 584g = 7896g
8. Arvutada 60%-lise väävelhappelahuse (=1,50g/cm3) molaarsus.
Lahendus:
Võtame 1L = 1000 cm3 H2SO4 lahuse, siis
m(H2SO4)60% lahus = *V = 1,50g/cm3*1000cm3 = 1500g
m(H2SO4) = 1500g*0,6 = 900g
n(H2SO4) = 900g/98g/mol = 9,18mol
c(H2SO4) = n/V = 9,18mol/1L = 9,18mol/L = 9,18M
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