Üldloodusteadus
NA
= 18,069 1013 (molekulid )
N ( H ) = 18,069 1013 2 = 36,138 1013 (aatomid )
m 46 10 -6
b)n( Na) = = = 2 10 -6 mol
M 23
N ( Na) = n N A = 2 10 -6 6 10 23 = 12 1017 (molekulid )
16) N ( Na) = 12 10 1 = 12 10 (aatomid )
17 17
Antud
a)m(H2)=6,023×10-10
b)M(Na)=23g/mol
m(Nat)=46mkg
a)N(H)=?
b)N(Na)=?
Vastus: N(H)=36,138×1013; N(Na)=12×1017
a )m( H 2O ) = V = 30 g
m 30
n( H 2 O) = = = 1,67(mol)
M 18
b)V ( H 2O ) = 0,5l = 500ml
m( H 2O ) = V = 500 g
m 500
n( H 2 O) = = = 27,8(mol )
M 18
N 1000
c )n(C6 H12O6 ) = = = 166,7 10 -23 (mol )
17) N A 6, 02 10 23
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