"427knm" - 1 õppematerjal

“RAUDBETOONKONSTRUKTSIOONID. PROJEKT”

b w = 200mm l0 = 0.85 l eff = 0.85 5000 = 4250mm 1 1 b eff = b w + l0 = 200 + 4250 = 1050mm < b = 2167mm 5 5 - Pikisuunas armeerimine 13  MSd = 56.1kNm Mf = fcd b eff hf ( d1 - 0.5 hf ) = = 0.85 13.3 1050 100 ( 410 - 0.5 100) = 427 10 6 Nmm Mf = 427kNm > MSd = 56.1kNm Järelikult ristlõigenuljoon vahelaeplaadi tsoonis MSd 56.1 10 6 µ= = = 0.0281 fcd b eff d12 0.85 13.3 1050 410 2 µ = 0.0281 < µ c = 0.393 = 1 - 1 - 2 µ = 1 - 1 - 2 0.0281 = 0.0285 fcd b eff d1 0.0285 0.85 13.3 1050 410 A S1 = = = 408mm2