"3i22" - 1 õppematerjal

Elektrotehnika 1 Kodutöö 1 Skeem 5

xxx kood xxx Tallinn 2015 Algandmed: Skeem nr. 5 R1 = R2 = R5 = R6 = 1Ω; R3 = R4 = 0,5Ω E1 = 3V; E5 = 5,5V; E6 = 2V 1. Arvutada haruvoolud I1…I6 kontuurvoolude meetodil I11*(R1+R2) + I22*R2 = E1 I22*(R2+R3+R4+R6) + I11*R2 – I33*R4 = E6 I33*(R4+R5) – I22*R4 = E5 2I11 + I22 = 3 I11 + 3I22 – 0,5I33 = 2 – 0,5I22 + 1,5I33 = 5,5 2. Arvutada haruvoolud I1…I6 sõlmepingete meetodil U10*G11 – U20*G12 = J11  3*U10 – U24 = 5 U10*G21 – U30*G23 = J22  G21 – 3*U30 = 3,5 – U20*G32 + U30*G33 = J33  – 3*U20 + 5*U30 = – 5,5 J11 = E1 /R1 + E1 /R1 = 3 + 2 = 5 J22 = E5 /R5 – E6 /R6 = 5,5 – 2 = 3,5 J33 = – E1 /R1 = – 5,5 G11 = 1/R1 + 1/R2 + 1/R6 = 1 + 1 + 1 = 3