describing the system. The frequency changes from 20 MHz to 18 MHz and the system samples at an interval of 2ms. How many counts does the microprocessor detect at, 2ms a) 20 MHz? =40000 counts 50 ns 2ms b) 18 MHz? =36 000 counts 55,55 ns What is the difference in terms of number of counts detected by the microprocessor? Between 20MHz and 18MHz are 4000 counts. Question 2 Consider the following diagram The frequency changes from 20 MHz to 18 MHz and the system samples at an interval of 100ns. a) What is the difference in terms of number of counts detected by the microprocessor? 10 MHz 10 MHz =5000 =5555,555 2000 Hz 1800 Hz Between 20MHz and 18MHz are 555,555 counts. b) Explain why this method results in higher resolution.
Microcontroller homework for week 07 1. A) 40000 counts B) 36000 counts The difference between 20MHz and 18MHz is 4000 counts. 2. A) 555,555 counts more B) Higher resolution is caused by increased sampling rate. 3. A) Because the mixer needs additional components B) The mixer approach multiplies the frequency shift you want to measure, but also any other frequency shift. This includes drift caused by component heating, noise, etc. 4. The output
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