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Homework 01
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Homework 01

a)1232= 61,5; 612=30,5; 302=15; 152=7,5; 72= 3,5; 32=1,5 (1111011) 0.456*2=0.912; 0,912*2=1,824; 0,824*2=1,648; 0,648*2=1,296; 0,296*2=0,592; 0,592*2=1,184; 0,184*2=0,368; 0,368*2=0,736; (0,736*2=1,472; 0,472*2=0,944; 0,944*2=1,888) So b)12316= 7,6875 ; 0,6875*16=11 ; 716 is less than one, then hex is 7B 0,456*16= 7,296 ; 0,296*16=4,736; 0,736*16=11,776; 0,776*16=12,416; 0,416*1...

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Microcontroller homework 2
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Microcontroller homework 2

SNR - Ratio of RMS signal to RMS SINAD - Ratio of the RMS signal amplitude to the mean value of the root-sum-square (RSS) ENOB - The effective number-of-bits and relates to SINAD THD - Ratio of the rms value of the fundamental signal to the mean value of the RSS of its harmonics. SFDR - Ratio of the RMS value of the signal to the RMS value of the worst spurious sig...

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Microcontroller homework 3
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Microcontroller homework 3

Treshold, sensitivity, (full) range, linearity, accuracy, precision, stability, hysteresis, noise 2. VO = RH(RT+RH) = 0.381356 V 3. A) 100 B) 212,464 4. A) B) R1 = 16,67 k C) ...

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Microcontroller homework 4
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Microcontroller homework 4

A) 40000 counts B) 36000 counts The difference between 20MHz and 18MHz is 4000 counts. 2. A) 555,555 counts more B) Higher resolution is caused by increased sampling rate. 3. A) Because the mixer needs additional components B) The mixer approach multiplies the frequency shift you want to measure, but also any other frequency shift. This includes drift caused by com...

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Microcontroller homework 5
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Microcontroller homework 5

PID control scheme: Equation describing the PID control: Differences between ,,bang-bang" control and proportional control: Proportional 0%...100% As error decreases, output decreases, e.g. reduces overshoot ,,Bang-bang" 0% or 100% Only 2 states (that's why also called Onoff control). It has feedback. Similar to PWM ouput signal. Integral and Derivative terms in the PID equation: These are tim...

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Microcontroller homework 6
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Microcontroller homework 6

Microcontroller homework for week 11 1. 2. I would choose schematic C because the Fly-Back on C is with zener-diode and on the output ­ two diodes are used, witch are placed correctly as are the resistors, so the schematic would function as required. ...

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Microcontroller homework 07
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Microcontroller homework 07

Three different stepper motors (illustrations on page 162-163): · permanent-magnet, · variablereluctance, · hybrid. The VR stepper has a soft iron rotor with teethand a wound stator. As current is applied to two opposing stator coils, the rotor is pulled into alignment with these twocoils. As the next pair of coils is energized, t...

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Homework 1 in Microcontrollers and practical robotics
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Homework 1 in Microcontrollers and practical robotics

456 - 64 = 59.456 1 59.456 - 32 = 27.456 1 27.456 - 16 = 11.456 1 11.456 - 8 = 3.456 1 3.456 - 4 = 0 3.456 - 2 = 1.456 1 1 0.456 * 2 = 0.912 0 0.912 * 2 = 1.824 1 0.824 * 2 = 1.642 1 0.642 * 2 = 1.284 1 0.284 * 2 = 0.568 0 0.568 * 2 = 1.136 1 0.136 * 2 = 0.272 0 0...

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Midterm Exam solutions and answers in Microcontroller and practical robotics
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Midterm Exam solutions and answers in Microcontroller and practical robotics

982 to (a) binary and (b) hex. Show all your calculations. a.) 101011.111110 b.) 2B.FB6 Question 2 Perform the calculation of 58 – 42 by first converting each decimal value to binary and then using the twos complement method. Show all your calculations 5810=001110102 4210=001010102 Converse to twos complement 4210=001010102=1...

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W11 Homework Solutions
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W11 Homework Solutions

pdf and Chapter_8_EMI_ElectroMagnetic_Interference.pdf Question 1 Given the below open sensor detection: a. Derive equations for both outputs VO and Vsense as a function of VR, R1, Rth, RH, RL and RF. b. What value will appear on each output if the thermistor fails (becomes an open circuit)? c. How can the above schem be modified to implement temperature reading with open sensor detection using only one ADC and one digital input pin...

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