Homework-04 Solution (100 marks) Read Chapter_4_Time_Based_Measurements.pdf Question 1 (10 marks) When converting an analogue value to a frequency, consider the following diagram describing the system. The frequency changes from 20 MHz to 18 MHz and the system samples at an interval of 2ms. How many counts does the microprocessor detect at, a) 20 MHz? b) 18 MHz? What is the difference in terms of number of counts detected by the microprocessor? Solution: 1 1 a) Converse 20 MHz to time length: T 0.00005ms f 20,000,000 2ms Number of counts in 2ms: N 40,000 0.00005ms 1 1 b) Converse 18 MHz to time length: T 0.000055556ms ...
Read Chapter_5_Output_Control_Methods.pdf Question 1 (10 marks) Draw a PID control scheme and write down an equation to describe the PID control. Compare the differences between the “bang-bang“ control and proportional control. What are the functions of Integral and Derivative terms in the PID equation. Solution: Draw a PID control system: (Figure 5.5, page 111) Write down an equation to describe the PID control: (page 111) Compare the differences and the advantages between the “bang-bang“ control and Proportional control: (page 105) “Bang-Bang“ control or ON-OFF control is the simplest control system. It turns ON when the system needs more INPUT and tuns OFF if the system doesn’t need INPUT any more. The INPUT is similar to the PWM square wave (running ON and OFF during the length of the needed INPUT). Bang-Bang control is similar to the PWM input signal Proportional control: Bang-Bang con...
Mictrocontroller Week 03 Numbering systems 1. Convert the decimal number 123.456 to the following formats, taking whole numbers and fractions into account. Show calculations. a) Binary Fractional part : Reading direction Integral part: Reading direction 0,456 x 2 = 0,912 0 123 / 2 = 61 1 0,912 x 2 = 1,812 1 61 / 2 = 30 1 0,812 x2 = 1,624 1 30 / 2 = 15 0 0,624 x 2 = 1,248 1 15 / 2 = 7 1 0,248 x 2 = 0,496 0 7/2=3 1 0,496 x 2 = 0,992 1 3/2=1 1 0 1 1 0 0 So 123.45610 = 0111 1011.0111 01002 b...
Question 1 Define the following ADC terms: 1. SNR – (Signal to Noise Ratio) SNR is a calculated value that represents the ratio of RMS signal to RMS noise. 2. SINAD - (signal-to-noise-and-distortion ratio) Ratio of the RMS signal amplitude to the mean value of the root-sum-square (RSS) 3. ENOB – (effective number of bits) The effective number-of-bits and relates to SINAD 4. THD - (total harmonic distortion) Ratio of the rms value of the fundamental signal to the mean value of the RSS of its harmonics. 5. SFDR - (spurious free dynamic range) Ratio of the RMS value of the signal to the RMS value of the worst spurious signal. 6. Channels - related to the inputs of the ADC can either be multiplexed or individually selected. 7. Linearity - relates to how a ADC follows a linear function. All ADCs are to a certain extend nonlinearity. 8...
Question 1 Name 9 characteristic parameters of sensors. Treshold, noise, range, stability, linearity, accuracy, precision, sensitivity, hysteresis Question 2 Given the circuit below (using a SYH-2R humidity sensor) determine the output voltage for a relative humidity of 70 % at 30 °C if R T = 50 kΩ and VDD= 2.5 V. R70 30 c =R H =9,2 kV RH 9,2 k V O= ∙ V DD= ∙ 2,5 = 0,388 V (R T + R H ) ( 50 k +9,2 k ) Hint: Check specification for Humidity Sensor of SYH-2R.pdf at http://www.rhopointcomponents.com/images/SYH-2R.pdf 2 Week 04 Homework Question 3 Given the following bridge circuit for a strain gauge, determine the value of the strain gauge resistance {RS}. Let: VIN = 5V R3 = 200 Ω R2 = 50 Ω R1 = 100 Ω a) Under no strain (VOUT = 0 V) R2 ∙ R3 RS= =100 Ω ...
Read Chapter_4_Time_Based_Measurements.pdf Question 1 When converting an analogue value to a frequency, consider the following diagram describing the system. The frequency changes from 20 MHz to 18 MHz and the system samples at an interval of 2ms. How many counts does the microprocessor detect at, 2ms a) 20 MHz? =40000 counts 50 ns 2ms b) 18 MHz? =36 000 counts 55,55 ns What is the difference in terms of number of counts detected by the microprocessor? Between 20MHz and 18MHz are 4000 counts. Question 2 Consider the following diagram The frequency changes from 20 MHz to 18 MHz and the system samples at an interval of 100ns. a) What is the difference in terms of number of counts detected by the microprocessor? 10 MHz 10 MHz =5000 =5555,555 2000 Hz 1800 Hz ...
Arvutivõrgud 3.12.2012 Merilin Kutser AT07-b http://www.vallaste.ee/ KOKKUVÕTTE Klient- Arvuti, mis kasutab andmetöötluseks serveri ressursse. Server- Võrguga ühendatud arvuti või seade, mis haldab võrgu ressursse. Klient/server võrk- Kliendid kasutavad läbi võrgu serverite poolt pakutavaid ressursse. Peremehelt-peremehele võrk(P2P)- Selline võrk, kus kõik laua- ja sülearvutid töötavad samaaegselt nii klientide kui serveritena ja jagavad oma faile kõigi teiste võrgus olevate kasutajatega ilma keskse serverita. Switch- Võrguseade, mis valib välja trakti või ahela, mida mööda andmeüksus saadetakse järgmisse võrgusõlme. Kommutaator võib lisaks teatud määral täita ka marsruuteri funktsioone, s.t. määrata kindlaks andmete liikumise marsruudi ja eekõige selle, millisesse lähimasse võrgupu...
EESTI MAAÜLIKOOL Tehnikakolledz Roman Koscikas TEHNIKA AJALOO VEDURINA referaat Tehnotroonika erialal Tartu 2012 Sisukord SISSEJUHATUS..................................................................................................................................3 Minevik.................................................................................................................................................4 Tänapäev...............................................................................................................................................5 Tulevik .................................................................................................................................................6 KASUTATUD KIRJANDUS...............................................................................................................7 SISSEJUHATUS Üldlevinud teadm...
Tallinna Polütehnikum Modem REFERAAT Juhendaja: Õpilane: Tallinna Polütehnikum Sisukord Tallinna Polütehnikum Sissejuhatus Modem on seade, mis moduleerib analoogsignaali, et edastada kodeeritud digitaalset sõnumit üle sidekanali ning demoduleerib sellise analoogsignaali, et dekodeerida saadud sõnum. Seadme eesmärk on tekitada signaal, mida on lihtne edastada ja mida on võimalik dekodeerida, et taastada esialgne info. Sõna "modem" on tuletatud inglise keele sõnadest modulate ja demodulate, mis tähendavad vastavalt "moduleerima" ja "demoduleerima". Modem kuidas toimib Modemite tuntuim näide on kõnesagedusala modem, mis muudab personaalarvuti digitaalsed andmed modelleeritud elektrilisteks signaalideks.Modelleeritud elektrilised signaalid on häälsageduse piires telefoni kanalil. Neid signaale saab edastada telefoni liinide...