docstxt/133656757994735.txt
L=1H R=7.9 f=79 Hz Ur=10V Fig. 1.1 Circuit diagram Calculations: =2f=2**79=496,4 rad/s XL=L=1*496,4 Z=SQRT(XL2+R2)=SQRT(496,42+7,92)=496,5 I=UR/R=10/7,9=1,3A U=I*Z=1,3*496,5=645,5V UMAX=SQRT(2)*U=912,9V =-arccos(R/Z)=-89° =-89°/(360*79)=-3,1*10-3 A=-20*log(Z/R)=-36 dB Comparative data table: Quantity Calculated value Experimental value I, A 1,3 1,308 ° -89 -89,118 , s -3,1*10-3 -3,2*10-3 A, dB -36 -36,254 ...
docstxt/127065387414363.txt
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$ 3 5.0E-6 10.20027730826997 50 5.0 50 L 648 64 552 64 0 1 false 5.0 0.0 L 648 104 552 104 0 1 false 5.0 0.0 L 648 136 552 136 0 1 false 5.0 0.0 L 648 168 552 168 0 0 false 5.0 0.0 L 648 296 536 296 0 0 false 5.0 0.0 L 648 328 536 328 0 0 false 5.0 0.0 L 648 360 536 360 0 0 false 5.0 0.0 L 648 392 536 392 0 0 false 5.0 0.0 x 505 76 531 82 0 24 a0 x 497 304 524 310 0 24 b0 154 808 72 872 72 1 2 5.0 150 808 112 872 112 1 2 0.0 w 872 288 840 288 0 w 872 264 872 288 0 w 872 256 840 256 0 w 872 224 840 224 0 w 872 248 872 224 0 152 872 256 920 256 1 3 0.0 150 792 288 840 288 1 2 0.0 150 792 256 840 256 1 2 0.0 150 792 224 840 224 1 2 0.0 w 808 80 664 80 0 w 664 88 664 104 0 w 680 64 648 64 0 w 680 64 808 64 0 w 664 104 664 120 0 w 664 120 664 296 0 w 664 296 648 296 0 w 664 120 808 120 0 154 760 160 824 160 1 2 5.0 154 824 168 888 168 1 2 5.0 w 680 72 680 96 0 w 800 96 800 104 0 w 800 104 808 104 0 w 696 104 648 104 0 w 696 104 696 152 0 w 6...
$ 1 5.0E-6 1.0312258501325766 50 5.0 50 L 80 96 48 96 0 0 false 5.0 0.0 150 432 64 512 64 0 2 0.0 150 432 160 512 160 0 2 5.0 150 432 240 512 240 0 2 5.0 150 432 336 512 336 0 2 5.0 150 432 432 512 432 0 2 5.0 152 656 240 736 240 0 5 5.0 w 432 48 144 48 0 w 144 48 144 96 0 w 112 96 112 128 0 I 128 128 192 128 0 0.5 w 144 96 112 96 0 w 112 96 80 96 0 w 128 128 112 128 0 w 432 416 208 416 0 w 432 320 208 320 0 w 432 224 208 224 0 w 192 128 208 128 0 w 208 128 208 224 0 w 208 224 208 320 0 w 208 320 208 416 0 L 112 192 48 192 0 1 false 5.0 0.0 I 128 176 192 176 0 0.5 w 128 176 112 176 0 w 112 176 112 192 0 w 192 176 336 176 0 w 336 176 336 80 0 w 336 80 432 80 0 w 112 192 112 256 0 w 112 256 432 256 0 L 96 320 48 320 0 0 false 5.0 0.0 L 112 400 48 400 0 1 false 5.0 0.0 I 112 320 176 320 0 0.5 w 112 320 96 320 0 w 176 320 176 208 0 w 176 208 352 208 0 w 352 208 352 144 0 w 352 144 432 144 0 w 176 320 176 352 0 w 176 352 432 352 0 w 432 448 ...
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$ 1 0.000005 10.20027730826997 50 5 50 L 624 96 624 64 0 0 false 5 0 L 656 96 656 64 0 0 false 5 0 L 688 96 688 64 0 0 false 5 0 L 720 96 720 64 0 0 false 5 0 x 664 47 685 50 4 32 A x 902 48 923 51 4 32 B L 960 96 960 64 0 0 false 5 0 L 928 96 928 64 0 0 false 5 0 L 896 96 896 64 0 0 false 5 0 L 864 96 864 64 0 0 false 5 0 L 1136 16 1104 16 0 0 false 5 0 L 1136 112 1104 112 0 0 false 5 0 I 1152 48 1184 48 0 0.5 5 I 1168 160 1200 160 0 0.5 5 150 1312 48 1360 48 0 2 5 5 150 1312 112 1360 112 0 2 0 5 150 1312 176 1360 176 0 2 0 5 150 1312 240 1360 240 0 2 0 5 w 1296 16 1136 16 0 w 1136 16 1136 48 0 w 1136 48 1152 48 0 w 1312 256 1136 256 0 w 1296 224 1312 224 0 w 1312 192 1200 192 0 w 1200 192 1200 160 0 w 1312 64 1200 64 0 w 1200 64 1200 160 0 w 1312 32 1184 32 0 w 1184 32 1184 48 0 w 1312 96 1184 96 0 w 1184 96 1184 48 0 w 1312 128 1152 128 0 w 1152 128 1152 112 0 w 1152 112 1136 112 0 w 1312 160 1296 160 0 w 1296 224 1296 160 0 w 1296 1...
Read Chapter_6_Analog_Outputs.pdf and Chapter_8_EMI_ElectroMagnetic_Interference.pdf Question 1 Given the below open sensor detection: a. Derive equations for both outputs VO and Vsense as a function of VR, R1, Rth, RH, RL and RF. b. What value will appear on each output if the thermistor fails (becomes an open circuit)? c. How can the above schem be modified to implement temperature reading with open sensor detection using only one ADC and one digital input pin of the microcontroller? Solution: a. Derive equations for both outputs as a function of VR, R1, Rth, RH, RL and RF. Rth Writing the equation for V1 : V1 VSense VR th R R1 V0 V2 VR V2 V2 Writing the equation for V2 : ...
docstxt/14145964572398.txt
$ 3 0.0 21.593987231061412 74 5.0 50 152 936 440 960 440 1 4 0.0 150 904 408 904 424 1 2 0.0 150 904 472 904 456 1 2 0.0 150 872 464 872 448 1 2 0.0 150 872 416 872 432 1 2 0.0 w 904 424 936 424 0 w 872 432 936 432 0 w 872 448 936 448 0 w 904 456 936 456 0 w 904 328 936 328 0 w 872 320 936 320 0 w 872 304 936 304 0 w 904 296 936 296 0 150 872 288 872 304 1 2 0.0 150 872 336 872 320 1 2 0.0 150 904 344 904 328 1 2 0.0 150 904 280 904 296 1 2 0.0 152 936 312 960 312 1 4 0.0 w 904 208 936 208 0 w 872 200 936 200 0 w 872 184 936 184 0 w 904 176 936 176 0 150 872 168 872 184 1 2 0.0 150 872 216 872 200 1 2 0.0 150 904 224 904 208 1 2 0.0 150 904 160 904 176 1 2 0.0 152 936 192 960 192 1 4 0.0 w 904 88 936 88 0 w 872 80 936 80 0 w 872 64 936 64 0 w 904 56 936 56 0 150 872 48 872 64 1 2 0.0 150 872 96 872 80 1 2 0.0 150 904 104 904 88 1 2 0.0 150 904 40 904 56 1 2 0.0 152 936 72 960 72 1 4 0.0 M 984 232 1016 232 0 2.5 M 984 208 1016 208 0 2.5 ...
docstxt/14145957950513.txt
Tallinn University of Technology Department of Electrical Engineering ELECTRONICS AND SEMICONDUCTOR ENGINEERING Exercises Linear circuits Student: xxxxxxxx Code: xxxxxx Group: xxxxxx TALLINN xxxx 1.1 RL-Circuit L1 100mH Uout=4V V1 232.5 Vrms R1 5kHz 54 -89° Figure .1: RL-circuit Figure 1.: Input and load ...
Taavi Rokka EGR MIS on Egr(Exhaust Gas Recirculation)? Heitgaaside tagastussüsteem Lämmastikoksiidide (NOx) kontsentratsiooni vähendamiseks väljalaskegaasides. *(NO ja NO2; MITTE: N2O) Lämmastikoksiide tekkimine sõltub põlemistemperatuurist. Kõrge põlemistemperatuur tuleneb lahjade küttesegude põletamisest. Heitgaaside tagasijuhtimine põlemiskambrisse vähendab põlemistemperatuuri ja rõhku. http://video.about.com/autorepair/What-Is-an-EGR-Car-Valve-.htm Aja lugu jms 1970ndad (1973) Sisemine- klapiajastus Välimine- klapiga 2000K Miks? Lämmastikoksiidide vähenemine: 1. Põlemisprotsessi jahutatakse, sest tagasijuhitud heitgaas neelab soojust. 2. Hapnikukoguse vähendamine põlemiskambrisse tagasijuhitud heitgaaside tõttu. 3. Tekib vähem heitgaase. Parem jahutus* Diiselmootoritel heitgaaside tagastus kuni 65% 1. Mootori pöörlemissagedus 2. Kütuse sissepritsekogus 3. Sisseimetava õhu kogus 4. Sisseimetava õh...
Tallinn University of Technology Department of Electrical Drives and Power Electronics Report on Exercises 2 Diodes Student ******* Code ****96 Group AAVB41 Tallinn 2012 2.1. Diode rectifier VD f = 9 kHz U=6V U = 19.7 V R = 96 k Figure 1. Circuit diagram Figure 2. Timing diagram VD + R = 96 k...
Midterm Exam Microcontrollers and Practical Robotics Question 1 Convert the decimal number 43.982 to (a) binary and (b) hex. Show all your calculations. a.) 101011.111110 b.) 2B.FB6 Question 2 Perform the calculation of 58 – 42 by first converting each decimal value to binary and then using the twos complement method. Show all your calculations 5810=001110102 4210=001010102 Converse to twos complement 4210=001010102=110101012+1=110101102 Then 58+(42) 001110102 +110101102 = 000100002 =1610 Question 3 Given the following bridge circuit for a strain gauge, determine the value of the strain gauge resistance {RS}. Let: VIN = 5V R3 = 100 Ω R2 = 50 Ω R1 = 100 Ω 2 Midterm Exam - Solutions a) Under no strain (VOUT = 0 V) b) When VOUT = 0,5 V {under strain}. Solution: a) Under no strain: R1 R3 R1R4 R2 R3 VOUT ...
Homework-04 Solution (100 marks) Read Chapter_4_Time_Based_Measurements.pdf Question 1 (10 marks) When converting an analogue value to a frequency, consider the following diagram describing the system. The frequency changes from 20 MHz to 18 MHz and the system samples at an interval of 2ms. How many counts does the microprocessor detect at, a) 20 MHz? b) 18 MHz? What is the difference in terms of number of counts detected by the microprocessor? Solution: 1 1 a) Converse 20 MHz to time length: T 0.00005ms f 20,000,000 2ms Number of counts in 2ms: N 40,000 0.00005ms 1 1 b) Converse 18 MHz to time length: T 0.000055556ms ...
Ticket No1 1)The characteristic is called output characteristic or volt-ampere charateristic of a Rectifier Diode. 2)Rectifier Diode. 3) A is called Anode and C is called Cathode. An Anode has positive potential and therefore collects electrons in the device. Cathode has negative potential and therefore emits electrons to anode. The symbol looks like an arrow that ponts from the anode to the cathode, and reminds that conventional current flows easily from the p side(anode) to the n side(cathode). BIASING. Forward biasing. If the current in a diode is too large, excessive heat will destroy the device. Even approaching the burnout current value without reaching it can shorten its life. Therefore manufacturer's data sheet specifies the maximum forward current, that diode can withstand. This average current IF is the rate a diode can handle up to the forward direction when used a...
Estonian Court System Estonia has a three-level court system. Estonian court system consists of four country courts, two administrative courts, three circuit courts and supreme court. Country courts and administrative courts are the courts of first instance, circuit courts are courts of appeal and the supreme court, situated in Tartu, is the court of the highest instance The Supreme Court is also the constitutional review court. In the structure of four country courts(Harju, Pärnu, Tartu and Viru) operate courthouses in every country seat(in Ida- Virumaa and Harjumaa there are three courthouses)In the structure of two administrative courts(in Tallinn and Tartu) there are four courthouses: in Tallinn, Tartu, Jõhvi and Pärnu. Three circuit courts are situated in Tallinn, Tartu and Jõhvi. The supreme court The Supreme Court is the court of the highest instance, which shall review decisions by way of cassation proceedi...
tutvu lausearvutuse keskkonnaga: http://logik.phl.univie.ac.at/~chris/gateway/formular-uk-zentral.html Millistel muutuja väärtustel on lause (Av(B&A))v(-A&(Cv(B&-C))) väär? Panna tuleb results only, 0 on väär 1 on õige Tutvu ajalooga saidis kuni II maailmasõda: http://www.maxmon.com/history.htm Loe läbi jutt ja proovi andmetega mängida: http://math.hws.edu/TMCM/java/DataReps/index.html Kahend süsteemi arvu(101101001) ->kümnend süsteemiks. Nr sisse ja bianarile punkt, ja vaatan base ten integeri kümnendarvudest annab Ecki appletis juuresoleva graafilise kujutise, teen kujundi ja vaatan base integeri mis vastab kahendsüsteemi arvule 1110001 ASCII tabelis? Nr sisse ja punkt bianari, vaatan ...teksti Kümnendsüsteemi arv 33 on kahendsüsteemis? 33 kirjutan ja Base-ten integer, vaatan bianary Loe läbi jutud Atbashi ja Caesari šifri (Caesar cipher) kohta: http://www.wikipedia.org 2 Tutvu ajalooga kuni 1970ndad: http://www.islandnet.com/~...
The Development of Reese Hoffa & Training Scheme for 2007 Season Reese Hoffa Development Table 1998 19.07m 1999 19.36m 2000 19.79m 2001 20.22m 2002 20.47m 2003 20.95m 2004 21.67m 2005 21.74m 2006 22.11m 2007 22.43m Hoffa Performance Progression Reese Hoffa Performance Progression 23 22 21 Distance (m) 20 19 18 17 16 Year 2001 2002 2003 2004 2005 2006 2007 1 Reese Hoffa Physical & Lifting P...
Read Chapter_4_Time_Based_Measurements.pdf Question 1 When converting an analogue value to a frequency, consider the following diagram describing the system. The frequency changes from 20 MHz to 18 MHz and the system samples at an interval of 2ms. How many counts does the microprocessor detect at, 2ms a) 20 MHz? =40000 counts 50 ns 2ms b) 18 MHz? =36 000 counts 55,55 ns What is the difference in terms of number of counts detected by the microprocessor? Between 20MHz and 18MHz are 4000 counts. Question 2 Consider the following diagram The frequency changes from 20 MHz to 18 MHz and the system samples at an interval of 100ns. a) What is the difference in terms of number of counts detected by the microprocessor? 10 MHz 10 MHz =5000 =5555,555 2000 Hz 1800 Hz ...
Tallinn University of Technology Department of Electrical Drives and Power Electronics Report on Exercises 2 on Electronics and Semiconductor Engineering Filters Student AAVB-41 Tallinn 2008 Exercise 2.1. Low-pass filter Circuit diagram Timing diagram and frequency responses High-pass filter Circuit diagram Timing diagram and frequency responses Calculations Quantity Calculated Experimental value value Umax, V 14,14 14,14 I, mA 0,0044 0,0044 UR, V 4,47 ...
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Test Generation name ____________________ 1. Small random circuit Manual test generation matricul. nr. ____________________ (100% coverage) group ____________________ Nr. Random Algorithmic 1 2 3 4 5 6 7 8 9 10 11 12 13 14 2. 8-bit adder Manual test generation Automatic test generation (ATPG) (100% coverage) (100% coverage) Nr. Algorithmic Default Tuned/Compacted 1 ...
Tallinn University of Technology Department of Electricl Power Engineering and Mechatronics Report on Exercises 2 on Power Electronics Single-Phase Full-Wave Rectifiers Tallinn 2017 Given parameters: Output voltage, Ud = 10 V Input frequency, fin = 50 Hz Load resistance, Rload = 70 kOhm Calculations: u1 10 I d= = =0.143 mA R L 70000 πUd 3.14∗10 US= = =11.1 V 2 √2 2 √2 U Smax =U S∗√ 2=11.1∗√ 2=15.7 V PIV =2∗U smax =2∗15.7=31.4 V I max=I d∗√ 2=0.143∗√ 2=0.2 V Table 1. Value comparison table. Parameter Calculated Measured Error Ud, V 10 9.6 0.3 Id, mA 0.143 0.137 0.006 Usmax...
Question 1 Name 9 characteristic parameters of sensors. Treshold, noise, range, stability, linearity, accuracy, precision, sensitivity, hysteresis Question 2 Given the circuit below (using a SYH-2R humidity sensor) determine the output voltage for a relative humidity of 70 % at 30 °C if R T = 50 kΩ and VDD= 2.5 V. R70 30 c =R H =9,2 kV RH 9,2 k V O= ∙ V DD= ∙ 2,5 = 0,388 V (R T + R H ) ( 50 k +9,2 k ) Hint: Check specification for Humidity Sensor of SYH-2R.pdf at http://www.rhopointcomponents.com/images/SYH-2R.pdf 2 Week 04 Homework Question 3 Given the following bridge circuit for a strain gauge, determine the value of the strain gauge resistance {RS}. Let: VIN = 5V R3 = 200 Ω R2 = 50 Ω R1 = 100 Ω a) Under no strain (VOUT = 0 V) R2 ∙ R3 RS= =100 Ω ...
Electrical engineering What is electrical engineering? Electrical engineering is a field of engineering that generally deals with the study and application of electricity, electronics, and electromagnetism Info about electrical engineering This field first became an identifiable occupation in the later half of the 19th century after commercialization of the electric telegraph, the telephone, and electric power distribution and use Subsequently, broadcasting and recording media made electronics part of daily life. The invention of the transistor, and later the integrated circuit, brought down the cost of electronics to the point they can be used in almost any household object. Famous people with big impact are Nikola Tesla, Alexander Graham Bell, john Logie Baird and many more How to become an electrical engineer Electrical engineers typically hold a degree in electrical engineering or electronic engineering. Getting into engineer...
Electrical drives and power electronics TESTS · The synchronous machines are associated with the names of Ferraris · Name the scientists who first studied electrical phenomena Coulomb · The DC machines are associated with the names of Jacobi Henry · The leading companies in the world market of electrical drive engineering are Mitsubishi · · The electromagnetic torque is born in air gap · What kind of drives the majority of drive systems present low accuracy · The induction machines are associated with the names of Dolivo-Dobrovolsky Tesla · One of the first eletrical motors has been built by Jacobi · Electromagnetic efficiency is measured in tesla · Time constants are measured by ms s hours · Who is the author of the first electrical motor Henry · Which rectifier cannot be built without a transformer 3-phase midpoint · Call the benefits of 3-phase rectifiers upon the 1-phase ones output voltage · Which rectifier has ...
Tallinn University of Technology Department of Electricl Power Engineering and Mechatronics Report on Exercises 3 on Power Electronics Three-Phase Rectifiers Tallinn 2017 Given parameters: Output voltage, Ud = 10 V Input frequency, fin = 50 Hz Load resistance, Rload = 70 kOhm Calculations: M3 rectifier: u1 10 I d= = =0.143 mA R L 70000 2π Ud 2 π∗10 U ¿max = = =12.09 V 3 √3 3 √3 U ¿ max 12.09 U ¿rms = = =8.55V √2 √2 B6 rectifier: πUd π∗10 U ¿max = = =6.05 V 3 √3 3 √3 U ¿ max 6.05 U ¿rms = ...
Tallinn University of Technology Department of Electricl Power Engineering and Mechatronics Report on Exercises 4 on Power Electronics AC Voltage Regulators Tallinn 2017 Given parameters: Output voltage, Ud = 20 V Input frequency, fin = 50 Hz Load resistance, Rload = 70 kOhm Calculations: U ¿ =2∗U out =2∗20=40V U max U rms = =17.09 V √2 Period = pulse width + delay => 10 ms = 5 ms + 5 ms Table 1. Control curve data. Delay time, Pulse with, Alpha, firing Switch SCR ms ms angle Uout, V Iout, mA Uout, V Iout, mA 0 10 0 28.14 ...
Analog Interfacing to Embedded Microprocessors Real World Design Analog Interfacing to Embedded Microprocessors Real World Design Stuart Ball Boston Oxford Auckland Johannesburg Melbourne New Delhi Newnes is an imprint of Butterworth–Heinemann. Copyright © 2001 by Butterworth–Heinemann A member of the Reed Elsevier group All rights reserved. No part of this publication may be reproduced, stored in a retrieval system, or transmitted in any form or by any means, electronic, mechanical, photocopying, recording, or otherwise, without the prior written permission of the publisher. Recognizing the importance of preserving what has been written, Butterworth–Heinemann prints its books on acid-free paper whenever possible. Library of Congress Cataloging-in-Publication Data Ball, Stuart R., 1956– Analog interfacing to embedded microprocessors : real world design / Stuart Ball. p. cm. ISBN 0-7506-7339-7 (pbk...
Kood: IGNITION SYSTEM 1 coil, distributor, low voltage 1a, 1b distributor with two separate circuits 2 breaker points magneto ignition 4 coil, distributor, high voltage 4a, 4b distributor with two separate circuits, high voltage 7 terminal on ballast resistor, to distributor 15 battery+ from ignition switch 15a from ballast resistor to coil and starter motor PREHEAT (Diesel engines) 15 preheat in 17 start 19 preheat (glow) STARTER 50 starter control BATTERY 15 battery+ through ignition switch 30 from battery+ direct 30a from 2nd battery and 12/24 V relay 31 return to battery- or direct to ground 31a return to battery- 12/24 V relay 31b return to battery- or ground through switch 31c return to battery- 12/24 V relay ELECTRIC MOTORS 32 return 33 ...
Eesti Infotehnoloogia Kolledž Digitaalloogika ja -süsteemid KODUTÖÖ kaugõpe Eesnimi Perenimi Matrikli nr. 10131846 Õpperühm DK21 Tallinn 2015 1. Leida oma matriklinumbrile vastav 4-muutuja loogikafunktsioon. Matriklinumber 10131846 on 16nd kujul 9A9986. 16nd kujul matriklinumber on vaja saada 7-kohaliseks. Selleks korrutan: 9A9986 * 7 = 43A32AA Saadud 16ndarvu 7 järguväärtust 0 . . . 15 määravad loogikafunktsiooni 1-de piirkonna. Seega 1-de piirkonda kuuluvad: 2, 3, 4, 10(A). Määramatuspiirkonna leidmiseks tuleb saadud 7-kohalist 16ndarvu korrutada veel niimitu korda 7-ga, kuni korrutamistulemus on 9-järguline: 43A32AA * 7 * 7 * 7 = 5A9F9E1C6. Tekkinud 16ndarvu need järguväärtused 0 . . . 15, mis ei kuulu juba 1-de piirkonda, moodustavad funktsiooni määramatuspiirkonna. Seega määramatuspiirkonda kuuluvad: 1, 5, 6, 9, 12(C), 14(E), 15(F). Ülejäänud arvud vahemikus 0....15 (mis pu...
Tallinn University of Technology Department of Electrical Drives and Power Electronics Report on Exercises 1 on Electronics and Semiconductor Engineering Linear Circuits Student AAVB-41 Tallinn 2008 Exercise 1.1. RL circuit Quantity Calculated Experimental value value Umax, V 14,14 14,14 I, mA 983 983 UR, V 9,82 9,81 UL, V 1,85 1,85 -10,7 -10,6 -2,0 -1,7 -0,15 -0,15 Comparative data table Conclusion Calculated and experimental results...
Test VIII - cumulative test by Piigli, Mets, Parker, Kauler "Top delusion" question / answers are red. Test I The induction machines are associated with the names of Dolivo - Dobrovolsky, Tesla. The synchronous machines are associated with the name of Ferraris. The DC machines are associated with the names of Jacobi and Henry. The electromagnetic torque is born in air gap. The torque is proportional to the current in dc motor. Which equations are correct? P = sW; oomega = tuletis fii'st The angular frequency is 2*pi()*n / 60 ja 2*pi()f The motor torque is equal to TL + J * oomega tuletis aja järgi The inductor supplies the motor with flux. The leading companies in the world market of electrical drive engineering are: Mitsubishi. The energy balance is described by energy conservation law. The armature supplies the motor with current. The cheapest and the most r...
Mictrocontroller Week 03 Numbering systems 1. Convert the decimal number 123.456 to the following formats, taking whole numbers and fractions into account. Show calculations. a) binary b) hexadecimal c) base-5 d) BCD === 1. a) 0111 1011.0111 01002 b) 7B.7416 c) 443.2125 d) 0001 0010 0011.0100 0101 01102 === 2. Extend the following unsigned 8-bit binary numbers to their 16-bit equivalents and convert the result to hexadecimal. a) 011010112 b) 101101012 === 2. a) 006B b) 00B5 === 3. Extend the following signed two’s complement 8-bit binary numbers to their 16-bit equivalents and convert the result to hexadecimal. a) 011010112 b) 101101012 === 3. a) 006B b) FFB5 === Logic and arithmetic 4. Using two’s complement arithmetic, calculate the following (choose a suitable number of bits for the representation): a) 121 – 185 b) -70 – 88 == 4. Convert back to verify answer == 5. Calculate the following without conve...
Question 1 (in wiki and in terminologies) 1. SNR is a calculated value that represents the ratio of root- mean-square (rms ) signal to rms noise. 2. SINAD stands for Signal-to-noise and distortion ratio. It is a measure of the quality of a signal from a communications device, often defined as: where is the average power of the signal, noise and distortion components. SINAD is usually expressed in dB. For examples to calculate the ratio of 1 kW (one kilowatt, or 1000 watts) to 1 W in decibels, use the formula 3. ENOB is the effective number-of-bits related to SINAD and the quality of a digitized signal. The 6.02 term in the divisor converts decibels (a log10) to bits (a log2) The 1.76 term comes from quantization error in an ideal ADC 4. THD - Total harmonic distortion is the ratio of the root-mean-square (rms) ...
Tallinn University of Technology Department of Electrical Drives and Power Electronics Report on Electronics and Semiconductor Engineering OP AMPS Student AAAB-41 Tallinn 2011 Exercise 5.1. Non.Inverting Voltage Amplifier Fig . Circuit diagram Fig . Diagrams of bandwidth versus gain. Data table Measur Calculated ed Uin R1, k R2, k KU Uout, V fc, kHz KU Uout, V fc, kHz 0,7 2 18,57 9,63 6,74 14...
Tallinn University of Technology Department of Electrical Drives and Power Electronics Report on Exercises 3 on Electronics and Semiconductor Engineering Diode circuits Student AAVB-41 Tallinn 2008 Exercise 3.1. Diode characteristics Fig. 3.1. Circuit diagram Timing diagram Output characteristic (forward bias only) Forward Bias Reverse Bias Umax, V UAC, Vrms Measured Calculated IA, Arms IA, Arms 0,5 0,35 0,006 0 1 0,64 0,1 0 2 1,05 4,71 ...
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My favorite city , Madrid. GEOGRAPHY Madrid is the capital of Spain. As the capital of Spain, Madrid is also the political, economic and cultural center of Spain. SPORT Madrid is the home to a football club giants Real Madrid. Real Madrid is one of the most prestigious football clubs of the world, having won a record 9 european cups. The City is also the host of the Circuito Permanente Del Jarama, a motorsport race circuit. Madrid hosts the largest bullring in Spain. It was established in 1929. Bullfighting season begins in March and ends in October. WHY DO I LIKE IT? I Chose Madrid for my presentation beacuse, it is a very cultural and a beautiful city.Madrid is also the home for many historical buildings like st. Barbaras curch, Arganzuela and Salamanca. Madrid is the European city with the higest number of trees and green surface. Summers are warm to hot and winters are cold to a bit under the freezing level. Thank you for Listening....
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